A stationary random process is sampled at time instants separated by 0.01 seconds. The resulting sample values are tabulated below. i 0 1 2 3 4 5 6 x(i) i 7 8 9 0.19 0.29 1.44 0.83 10 -0.01 11 - 1.23 12 - 1.47 13 x(i) - 1.24 -1.88 -0.31 1.18 1.70 0.57 0.95 i 14 15 16 17 18 19 20 x(i) 1.45 -0.82 -0.25 0.23 -0.91 -0.19 0.24 a) Estimate the mean value of this process. b) If the process has a true variance of 1.0, find the variance of your estimate of the mean.
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- D and E will add follow up questionThe grade point averages (GPA) for 12 randomly selected college students are shown on the right. Complete parts (a) through (c) 25 3.2 2.6 O below. 1.7 0.7 4.0 Assume the population is normally distributed. 2.3 1.3 3.8 0.4 2.3 3.3 (a) Find the sample mean. x- (Round to two decimal places as needed.)Percentage of 18- to 24-year olds living in parents' homes Refer to the figure at the right. At a = 0.05, can you support the claim that the proportion of men ages 18 to 24 living in parents' homes was greater in 1999 than in 2005? Assume the survey included 13,400 men and 13,600 women in 1999 and 13,900 men and 13,500 women in 2005, and assume the samples are random and independent. 707 55.9% 53.5% 41.8% 43% 0- 1999 2005 Men Women Identify the null and alternative hypotheses. Choose the correct answer below. O B. Ho: P1 > P2 O A. Ho: P1 > P2 Ha: P1 P2 O D, Ho: P1 P2 Find the critical value. The critical value is zo = 1.64 . (Round to two decimal places as needed.) Find the standardized test statistic. (Round to two decimal places as needed.)
- Freshmen GPAs First-semester GPAS for a random selection of freshmen at a large university are shown. Estimate the true mean GPA of the freshman class with 90% confidence. Assume a 0.62. Round Intermediate and final answers to two decimal places. Assume the population is normally distributed. 3.0 3.2 2.8 2.7 2.5 1.9 2.0 2.7 3.8 3.0 2.8 3.3 2.7 2.9 2.0 3.2 1.9 2.8 2.2 4.0 1.9 2.8 2.0 2.7 3.9 Send data to Excel AFWA sampling distribution (dotplot) for the mean quiz score for a sample n = 30 of STAT101 students is shown below. It was constructed using random samples from population data. What does one dot in this dotplot represent?Parts a-d
- STRATIFIED Random Sampling 1. Below is the number of students taking up statistics from each department. A seminar will be conducted outside the campus: Table 1: Number of Students enrolled in Statistics Course Number of Percent (c) (d) students (0.0000) (whole no.) (whole no.) Nursing 1,120 HRM 589 Engineering 557 IT 434 Total 2,700 a. Which between the 3% and the 5% margin of error will allow the department to work within the budget? Justify your answer. b. At 5% margin of error, how many participants should be taken as samples? c. Using proportional allocation, how many participants will be taken from each department (refer to n in "b")? d. Using equal allocation, how many participants will be taken from each department (refer to n in "b")?Question Help ▼ Test the claim about the difference between two population means u, and u, at the level of significance a. Assume the samples are random and independent, and t populations are normally distributed. Claim: µ, sH2; a = 0.05. Assume o, #o Sample statistics: X, = 2420, s, = 170, n, = 13 and X, = 2296, s, = 50, n, = 10 Identify the null and alternative hypotheses. Choose the correct answer belew. O A. Ho: H1 SH2 O B. Ho: H1 H2 O F. Ho: H1 = H2 Ha: H1 SH2 Ha: H1 # H2 Find the standardized test statistic t. t3= (Round to two decimal places as needed.) Find the P-value. P = (Round to three decimal places as needed.) Click to select your answer(s).The high temperatures (in degrees Fahrenheit) of a random sample of 46 small towns are: 99.3 97.9 98.4 98.9 98.2 99.8 99.6 97.5 98.3 98.7 96.3 99 97.1 97.8 96.6 96.4 99.2 99.8 99.4 99.4 99.7 96.7 99.5 99.3 97.2 97.7 98.5 98.5 98.8 98 98.6 98.9 97 99.9 97.3 96.8 96.7 98.4 98.3 99.9 98.7 99.2 97.6 96.9 97.6 98.8 Assume high temperatures are normally distributed. Based on this data, find the 90% confidence interval of the mean high temperature of towns. Enter your answer as an open-interval (i.e., parentheses with a comma) accurate to two decimal places (because the sample data are reported accurate to one decimal place).90% C.I. = Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.
- - X i Data Table Share Detail (x,) Sample (x2) 0.256 0.103 0.618 0.276 0.098 0.685 0.269 0.108 0.620 0.274 0.108 0.893 0.261 0.101 0.428 0.262 0.03 0.231 0.27 0.082 0.572 0.26 0.085 0.426 0.271 0.103 0.632 0.263 0.085 0.511 0.266 0.081 0.459 0.255 0.103 0.468 0.266 0.092 0.350 e table d all te 0.265 0.07 0.268 0.267 0.106 0.500 0.264 0.111 0.411 0.265 0.097 0.556 0.258 0.066 0.309 0.272 0.115 0.662 0.271 0.135 0.626 Print Done45