Several months ago while shopping, I was interviewed to see whether or not I'd be interested in signing up for a subscription to a yoga app. I fall into thecategory of people who have a membership at a local gym, and guessed that, like me, many people in that category would not be interested in the app. Myfriend Keiko falls in the category of people who do not have a membership at a local gym, and I was thinking that she might like a subscription to the app. Afterbeing interviewed, I looked at the interviewer's results. Of the 81 people in my market category who had been interviewed, 12 said they would buy asubscription, and of the 118 people in Keiko's market category, 36 said they would buy a subscription.Assuming that these data came from independent, random samples, can we conclude, at the 0.01 level of significance, that the proportion p, of all mallshoppers in my market category who would buy a subscription is less than the proportion p, of all mall shoppers in Keiko's market category who would asubscription?Perform a one-tailed test. Then complete the parts below.Carry your intermediate computations to three or more decimal places and round your answers as specified in the parts below. (If necessary, consult a list offormulas.) (a) State the null hypothesis H, and the alternative hypothesis H,.-1Ho :0合(b) Determine the type of test statistic to use.(Choose one)OSO(c) Find the value of the test statistic. (Round to three or more decimal places.)Equals(d) Find the p-value. (Round to three or more decimal places.)(e) Can we conclude that the proportion of mall shoppers in my market categorywho would buy a subscription is less than the proportion in Keiko's marketcategory who would?OYes No

Answered: Image /qna-images/answer/43e5e994-219b-4cde-b6d4-58f799599821.jpg

Answered: (a) State the null hypothesis H, and…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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1.12 To collect data in an introductory statistics course, I gave the students a questionnaire. One question asked whether the student was a vegetarian. Of 25 students, 0 answered study of 100 women suffering from excessive menstrual bleeding considers yes. They were not a random sample, but use these data to illustrate inference for a proportion. Let π denote the population proportion who would say yes. Consider H0: π = 0.50 and Ha: π ̸= 0.50. What happens when you conduct the Wald test, which uses the estimated standard error in the z test statistic? Find the 95% Wald confidence interval (1.3) for π. Is it believable? Conduct the score test, which uses the null standard error in the z test statistic. Report and interpret the P -value. Verify that the 95% score confidence interval equals (0.0, 0.133). (This is similar to the interval (0.0, 0.137) obtained with a small-sample method of Section 1.4.3, inverting the binomial test with the mid P -value.)
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7.Statistics Quiz
8.3 Inference for Quantitative Variable: Comparing Two Means Pulse Rates Mr. Wilcox's class performed an experiment to investigate whether drinking a caffeinated beverage would increase pulse rates. Twenty students in the class volunteered to take part in the experiment. All of the students measured their initial pulse rates (in beats per minute). Then Mr. Wilcox randomly assigned the students into two groups of 10. Each student in the first group drank 12 ounces of cola with caffeine. Each student in the second group drank 12 ounces of caffeine-free cola. All students then measured their pulse rates again. The table displays the change in pulse rate for the students in both groups. Construct and interpret a 95% confidence interval for the difference in true mean change in pulse rate for subjects like these who drink caffeine versus who drink no caffeine. Change in pulse rate (Final pulse rate - Initial pulse rate) 5 6 1 4 4 1 2 -1 Caffeine 8 No caffeine 3 3 -2 1 -1 STATE the parameter…
a. The sample proportion is enter your response here. (Round to two decimal places as needed.) Part 2 The sample proportion from this study is the ▼ expected observed proportion of adults in the ▼ sample population that ▼ disapprove approve of the government surveillance program. b. What are the hypotheses for the one-proportion z-test? H0: p=enter your response here; Ha: p ▼ greater than> not equals≠ less than< equals= enter your response here (Type integers or decimals.) What is the test statistic? z=enter your response here (Round to two decimal places as needed.) Identify the P-value. The P-value is enter your response here. (Round to three decimal places as needed.) What is the conclusion of the hypothesis test? A. Do not reject H0; the data do not provide sufficient evidence to conclude that a majority of adults in the country disapprove of the government surveillance program. B. Reject H0;…
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A population of scores has a mean of µ=89, a median of 87 and a mode of 85. What is the most likely shape for the population distribution? Symmetrical Positively skewed Negative skewed It cannot be determined from the information given O O
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NEED ASAP answer 8,9,10 only

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