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A standing wave on a string of length L = 2 m is given by: y(x,t) = 4 sin(2rtx)cos(120Ttt), where x and y are in centimetres and t is in seconds. The transverse speed of an element on the rope located at x = 15 cm at t = 2.3 s is: O v(x,t) = 60 m/s v(x,t) = 480n cm/s O v(x,t) = 60 cm/s v(x,t) = 0 cm/s

A standing wave on a string of length L = 2 m is given by: y(x,t) = 4 sin(2rtx)cos(120Ttt), where x and y are in centimetres and t is in seconds. The transverse speed of an element on the rope located at x = 15 cm at t = 2.3 s is: O v(x,t) = 60 m/s v(x,t) = 480n cm/s O v(x,t) = 60 cm/s v(x,t) = 0 cm/s

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A standing wave on a string of length L = 2 m is given by: y(x,t) = 4 sin(2Ttx)cos(120rt), where x and y are in centimetres and t is in seconds. The transverse speed of an element on the rope located at x = 15 cm at t = 2.3 s is: v(x,t) = 60 m/s %3! v(x,t) = 480n cm/s v(x,t) = 60 cm/s O v(x,t) = 0 cm/s
Transcribed Image Text:A standing wave on a string of length L = 2 m is given by: y(x,t) = 4 sin(2Ttx)cos(120rt), where x and y are in centimetres and t is in seconds. The transverse speed of an element on the rope located at x = 15 cm at t = 2.3 s is: v(x,t) = 60 m/s %3! v(x,t) = 480n cm/s v(x,t) = 60 cm/s O v(x,t) = 0 cm/s
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