A standing wave on a stretched string fixed at both ends is described by: y(x,t) =0.1 sin(2rtx) cos(100Ttt). The string has a length L = 1 m. For t > 0, an element on%3D%3Dthe string located at x = 0.75 cm would have a zero speed for the first time at:O t= 0.01 secO t= 0.025 secO t- 0.015 secO t- 0.0005 sect = 0.02 sec

Solution: Given that, The equation of standing wave is: y(x,t)=0.1 sin(2πx)cos(100πt)

A standing wave on a stretched string fixed at both ends is described by: y(x,t): 0.1 sin(2Ttx) cos(100rtt). The string has a length L = 1 m. For t > 0, an element on %3D %3! the string located at x = 0.75 cm would have a zero speed for the first time at: O t= 0.01 sec O t= 0.025 sec O t= 0.015 sec O t= 0.005 sec t = 0.02 sec

A standing wave on a stretched string fixed at both ends is described by: y(x,t): 0.1 sin(2Ttx) cos(100rtt). The string has a length L = 1 m. For t > 0, an element on %3D %3! the string located at x = 0.75 cm would have a zero speed for the first time at: O t= 0.01 sec O t= 0.025 sec O t= 0.015 sec O t= 0.005 sec t = 0.02 sec