A standard solution is prepared by completely dissolving 0.4 grams of CaCl2 and 0.2 grams of MgCO3 salts in 1-Liter DI water in a glass bottle closed to the atmosphere. The equilibrium pH of the standard solution is adjusted to 7.3 using acid-base solutions. Assuming the amounts of acid and based used in the initial pH adjustment is negligible, calculate : Temporary and permanent hardness of the solution as mg/L CaCO3. Total alkalinity and acidity as mg/L CaCO3. Useful information for problem :
A standard solution is prepared by completely dissolving 0.4 grams of CaCl2 and 0.2 grams of MgCO3 salts in 1-Liter DI water in a glass bottle closed to the atmosphere. The equilibrium pH of the standard solution is adjusted to 7.3 using acid-base solutions. Assuming the amounts of acid and based used in the initial pH adjustment is negligible, calculate : Temporary and permanent hardness of the solution as mg/L CaCO3. Total alkalinity and acidity as mg/L CaCO3. Useful information for problem :
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A standard solution is prepared by completely dissolving 0.4 grams of CaCl2 and 0.2 grams of MgCO3 salts in 1-Liter DI water in a glass bottle closed to the atmosphere. The equilibrium pH of the standard solution is adjusted to 7.3 using acid-base solutions. Assuming the amounts of acid and based used in the initial pH adjustment is negligible, calculate :
- Temporary and permanent hardness of the solution as mg/L CaCO3.
- Total alkalinity and acidity as mg/L CaCO3.
Useful information for problem :
![CT,CO3 = [H₂CO₂] + [HCO3] + [CO²-]
H₂CO3 ↔ HCO3 + H+
= 10-6.3
= 10-10.3
HCO3 ↔ CO²¯ + H+
Και
Kaz](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F393037b2-7449-4bd7-a188-129f813a1361%2Fe4f63f19-8ae4-4e9b-8f49-98faf631a1f3%2F57w0z6e_processed.png&w=3840&q=75)
Transcribed Image Text:CT,CO3 = [H₂CO₂] + [HCO3] + [CO²-]
H₂CO3 ↔ HCO3 + H+
= 10-6.3
= 10-10.3
HCO3 ↔ CO²¯ + H+
Και
Kaz
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