A staggered bolted connection has bolts arranged as shown. Diameter of bolts is 21 mm. Fy = 248 MPa. Calculate the net area (sq. mm) along fracture line passing through bolts 2 and 3 only. Use w = 4.8 x100 mm and t = 16 mm.

A staggered bolted connection has bolts arranged as shown. Diameter of bolts is 21 mm. Fy = 248 MPa. Calculate the net area (sq. mm) along fracture line passing through bolts 2 and 3 only. Use w = 4.8 x100 mm and t = 16 mm.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: 9.9 A No. 32 (metric designation) reinforcing bar for concrete has a diameter of 32 mm. The bar is…

Q: A PL ½ x 8 tension member is connected with six 1-inch diameter bolts as shown in the figure below.…

A: Answer We are given Plate 1/2 x 8 bolt diameter = 1 in A36 steel Shear lag factor U = 0.1

Q: For the given riveted connection shown, having the allowable stresses: Fy = 248 MPa Fy = 150 MPa…

Q: 2. A connection is made from two 1.9 cm bolts in parallel, placed on a 21.6 cm wide steel bar. The…

A: Given data:- Diameter of bolts,d = 1.9 cm Thickness of steel bar, t = 2.54 cm Ultimate strength of…

Q: Material Strengths: Fy = 248 MPa, Fu = 400 M Pa For the two lines of bolt holes, the pitch is the…

Q: . Two wooden planks, each 20 mm thick and 160 mm wide, are joined by the glued mortise joint shown.…

A: Given values: Load P = 8 KN Thickness, t = 20 mm Width, w = 160 mm Average shearing stress = 820 KPa…

Q: Problem 4: Find the design moment strength for the following section: f'c = 7000 psi Es = 29,000 ksi…

A: Stress strain curve reinforcing steel,

Q: W P'

Q: Determine the maximum factored LRFD tensile force capacity in tension only (no block shear). The…

A: We know that Maximum factored LRFD tensile force capacity of the member is given by minimum of the…

Q: Match the cross-sections with the appropriate object and cutting plane for the problems shown below.…

A: Engineering drawing

Q: Question 3) The tension member shown in Figure 1 contains holes for in. bolts. At what spacing, s,…

A: We need to calculate spacing between two bolts.

Q: Shear strength value τ = 200 MPa The contents associated with bolts are given. P = 70 kN required…

A: Given, P =70 kNτ = 200 MPa

Q: Compute A,, and A, for a 14-in.-wide and ½-in.-thick plate subject to tensile loading with staggered…

A: Given : Width = 14 inches Thickness = 1/2 inches Compute An and Ae for the given plate ?

Q: A staggered bolted connection has bolts arranged as shown. Diameter of bolts is 21 mm. Fy = 248 MPa.…

A: Bolted joints are one of the most well-known components in development and machine plan. They…

Question

A staggered bolted connection has bolts arranged as shown.
Diameter of bolts is 21 mm. Fy = 248 MPa.
Calculate the net area (sq. mm) along fracture line passing
through bolts 2 and 3 only. Use w = 4.8 x100 mm and t = 16
mm.
Write your final answer in whole number
60mm 60mm
100mm
100mm
100mm
1
O 4
2
100mm
W

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Introduction

VIEW

Step 2: Net area along fracture line passing through bolts 2 and 3 only

VIEW

Solution

VIEW

Step by step

Solved in 3 steps with 10 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Solve the problem-CIvil Thanks
15. determine the capacity of the details shown below.A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksio) what is the block shear rupture (U-shaped) capacity of flange plate of the flange connection in kips? (2 decimal places)
Number of full joints (J1)?
A beam cross-section is limited to the size shown. Determine the required area of reinforcement for service load moments Mp = 400 ft-kips and ML = 250 ft-kips. Check crack control requirements f = 4000 psi (normalweight) f, = 60,000 psi d' = 2.5" b= 12" A's d₁= 32"
Determine the capacity of the details shown below. A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksi f) what is the block shear rupture capacity of the shear plate of the shear connection in kips? (2 decimal places)
| * A's O As,web As bw Steel areas: A's-2 + 14 = 308 mm² A₁=50 mm² (area of $8) Materials : C25/30 / B420C Longitudinal reinforcements A's=2 $ 14 As,web= 2 $ 12 As= 5 0 14 bw=300 mm d=670 mm d'=30 mm k₁= 0,85 k3 = 0,85 Pb=0.0205 (from table) Transverse Reinforcements $8/200 mm (2-leg stirrups) Material coefficients Ymc:1.5 (Concrete) Yms: 1,15 (Steel) Determine the reinforcement ratio and failure type of the beam As,web= 212= 226 mm² Asw=2x50=100 mm² (Total Area of two leg stirrup) A₁= 5 + 14=770 mm²
An A36 tension member shown in the figure is connected with three 19 mm diamter bolts. Diameter of hole = 22mm. Properties of 150 mm x 100 mm x 12.5 mm angle A = 3065 mm2 y = 50.55 mm Fy = 248 MPa Fu = 400 MPa Determine the desire strength due to fracture in the net section. Use U = 0.85 kN
Two steel plate tension members have been connected using 0.72 inch diameter bolts arranged in an equally-spaced 9 by 3 rectangular formation. Both plates have a thickness equal to 1/3 in. Take shear fracture stress as 51.2 ksi, clear distance for each edge bolt as 0.12 in, and the clear distance for the other bolts as 1.072 in. a)Sketch the connection showing all the details and measurements with units. b)Find the maximum allowable service dead load and live load assuming live load is half as much as dead load. Consider ASD.
Answer the following for the section at Point D Only Calculate the distributed load "w" that: Will cause the section crack Will cause the reinforcement to yield. Material Properties: F'c = 5000 psi Fy = 60000 psi Es = 29000000 psi Ln = 27 ft L wl₂² 16 wl,² 14 CD L wl,2 vl₁² 10 11 win² 16 h: 28 in A=4 in² b=14 in n d: 25 in
Please help with the problem below
The beam shown has the following properties. f’c= 30 MPa, fc=13.5 MPa, fy=400 MPa, fs=200MPa. c) The cracked section properties Kd and ICR.
Two wood boards, each 17 mm thick, are joined by the glued finger joint shown. The finger joint will fail when the average shear stress in the glue reaches 1045 kPa. Determine the shortest allowable length d of the cuts if the joint is to withstand an axial load of P = 6.2 kN. Use a = 26 mm and b = 208 mm. Glue b P P Answer: d= i mm