A square of side length a = 18.0 cm is placed so its lower-left corner is at the origin of a 2D coordinate system.The mass of the square is 3 kg and is distributed uniformly.(a) What is the position of the centre of mass of this square?RCOM= [XCOM, yCoM]m(b) A smaller square of area 4.0 cm² is removed from the larger square, leaving a hole centred on [4.00, 6.00]cm? How much mass was removed?mremoved=kg(c) What is the new centre of mass of the system?RCOM,new = [XCOM, yCoM]m

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Answered: A square of side length a = 18.0 cm is…

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