A square metal plate 1.8 m side and 1.8 mm thick weighing 60 N is to be lifted through a vertical gap of 30 mm of infinite extent (Fig. (1)). The oil in the gap has a specific gravity of 0.95 and viscosity of 3 N.s/m². If the metal plate is to be lifted at a constant speed of 0.12 m/s, find the force required.

Q: A shaft (250 mm diameter) rotates at 250 rpm inside a sleeve (251 mm diameter) with a constant…

A: Given:d=250 mmN=250 rpmdo=251 mmP=2204 WL=150 mmh=do-d2=0.251-0.2502h=0.0005 m

Q: A weight, as shown in figure Q1b-(a) has to move at constant velocity of 2 m/s on an inclined…

A: Given , Weight of the block, W =200 N velocity of the block , V = 2m/s Block width ,b =20 cm…

Q: Assuming we have a fluid with SG=0.6, and height of fluid in the piezometer tube equal to h=10m,…

A: The specific gravity of fluid S.G=0.6 The height of point P,M and S from free surface h=10 m

Q: A hydrodynamic journal bearing is subject to 2000 N load at a rotational speed of 2000 rpm Both…

A:

Q: The picture below depicts a system for delivering chocolate ganache in liquid form. The nozzle on…

A: given : inner diameter of hose =25mm  specfic gravity of chocolate=1.1  dynamic viscocity of…

Q: The distance between two horizontal plates is 16mm and filled with oil of viscosity 1.75 x…

A: Given data: Distance between two horizontal plates y=16 mm=0.016 m Viscosity μ=1.75×10-3 Poise 1…

Properties of Fluids

The term fluid represents a type of substance that can easily change its shape under any external pressure/force and can flow. Fluids can acquire any shape in which it is stored and can resist normal stresses but cannot resist shear stress in rest condition. Whenever external shear stress is applied to fluids, it starts to flow. The fluids may be liquid or gas. Example- water, air, etc.