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A square footing is 1.8 x 1.8 m² with a 0.4 x 0.4 m? square column. It is loaded WILH AA zria! Joad of 1800 kN and Mx = 810 kN.m; My= 260 kN.m. Undrained triaxial tests give d'=36° and c'=20 kPa. The footing depth D= 1.8 m, the soil unit weight y = 18 kN/m³, the water table is at a depth of 4.2 m from the ground surface. What is the ultimate load Qu by using general bearing capacity equation. %3D %3D Given (4- (0.62 ,0.66 ,0.68 (0.72) and - (0.20 (0.24),0.28,0.32) L

A square footing is 1.8 x 1.8 m² with a 0.4 x 0.4 m? square column. It is loaded WILH AA zria! Joad of 1800 kN and Mx = 810 kN.m; My= 260 kN.m. Undrained triaxial tests give d'=36° and c'=20 kPa. The footing depth D= 1.8 m, the soil unit weight y = 18 kN/m³, the water table is at a depth of 4.2 m from the ground surface. What is the ultimate load Qu by using general bearing capacity equation. %3D %3D Given (4- (0.62 ,0.66 ,0.68 (0.72) and - (0.20 (0.24),0.28,0.32) L

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Given (4- A sTIere footing is 1.8 x 1.8 m with a 0.4 x 0.4 m2 square column. It is loaded with an arial load of 1800 kN and Mx = 810 kN.m; My= 260 kN.m. Undrained triaxial tests give -36° and c'=20 kPa. The footing depth D = 1.8 m, the soil unit weight y = 18 kN/m³, the water table is at a depth of 4.2 m from the ground surface. What is the ultimate load Qu by using general bearing capacity equation. → (0.62 ,0.66 ,0.68(0.72) and 2- (0.20 (0.24), 0.28 ,0.32) -> L
Transcribed Image Text:Given (4- A sTIere footing is 1.8 x 1.8 m with a 0.4 x 0.4 m2 square column. It is loaded with an arial load of 1800 kN and Mx = 810 kN.m; My= 260 kN.m. Undrained triaxial tests give -36° and c'=20 kPa. The footing depth D = 1.8 m, the soil unit weight y = 18 kN/m³, the water table is at a depth of 4.2 m from the ground surface. What is the ultimate load Qu by using general bearing capacity equation. → (0.62 ,0.66 ,0.68(0.72) and 2- (0.20 (0.24), 0.28 ,0.32) -> L
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