A spring is attached to an inclined plane as shown in the figure. A block of mass  m = 2.61 kg  is placed on the incline at a distance  d = 0.279 m  along the incline from the end of the spring. The block is given a quick shove and moves down the incline with an initial speed  v = 0.750 m/s.  The incline angle is  θ = 20.0°,  the spring constant is  k = 535 N/m,  and we can assume the surface is frictionless. By what distance (in m) is the spring compressed when the block momentarily comes to rest

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A spring is attached to an inclined plane as shown in the figure. A block of mass 

m = 2.61 kg

 is placed on the incline at a distance 

d = 0.279 m

 along the incline from the end of the spring. The block is given a quick shove and moves down the incline with an initial speed 

v = 0.750 m/s.

 The incline angle is 

θ = 20.0°,

 the spring constant is 

k = 535 N/m,

 and we can assume the surface is frictionless. By what distance (in m) is the spring compressed when the block momentarily comes to rest?

### Problem Description

A spring is attached to an inclined plane as shown in the figure. A block of mass \( m = 2.61 \, \text{kg} \) is placed on the incline at a distance \( d = 0.279 \, \text{m} \) along the incline from the end of the spring. The block is given a quick shove and moves down the incline with an initial speed \( v = 0.750 \, \text{m/s} \). The incline angle is \( \theta = 20.0^\circ \), the spring constant is \( k = 535 \, \text{N/m} \), and we can assume the surface is frictionless. By what distance (in m) is the spring compressed when the block momentarily comes to rest?

### Diagram Explanation

The diagram illustrates a spring attached horizontally to an inclined plane. There is a block of mass \( m \) located on the incline. An arrow indicates the initial velocity \( \vec{v} \) of the block down the incline. The distance \( d \) represents the initial displacement of the block from the spring. The spring is indicated by a zig-zag line, symbolizing its potential to compress. The angle \( \theta \) denotes the inclination angle of the plane with respect to the horizontal ground.
Transcribed Image Text:### Problem Description A spring is attached to an inclined plane as shown in the figure. A block of mass \( m = 2.61 \, \text{kg} \) is placed on the incline at a distance \( d = 0.279 \, \text{m} \) along the incline from the end of the spring. The block is given a quick shove and moves down the incline with an initial speed \( v = 0.750 \, \text{m/s} \). The incline angle is \( \theta = 20.0^\circ \), the spring constant is \( k = 535 \, \text{N/m} \), and we can assume the surface is frictionless. By what distance (in m) is the spring compressed when the block momentarily comes to rest? ### Diagram Explanation The diagram illustrates a spring attached horizontally to an inclined plane. There is a block of mass \( m \) located on the incline. An arrow indicates the initial velocity \( \vec{v} \) of the block down the incline. The distance \( d \) represents the initial displacement of the block from the spring. The spring is indicated by a zig-zag line, symbolizing its potential to compress. The angle \( \theta \) denotes the inclination angle of the plane with respect to the horizontal ground.
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