A block of mass m = 1.5 kg is attached to a spring with a spring constant k. The position of the block as function of time is given by: x(t) = 0.2 cos(10t+n/2). Deduce the spring constant, k, and the total energy of the system: O k = 150 N/m and E = 15 J O k = 150 N/m and E = 3 J O k = 200 N/m and E = 20 J Ok= 200 N/m and E = 4 J

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Chapter1: Units, Trigonometry. And Vectors
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A block of mass m = 1.5 kg is attached to a spring with a spring constant k. The
position of the block as function of time is given by: x(t) = 0.2 cos(10t+n/2).
Deduce the spring constant, k, and the total energy of the system:
k = 150 N/m and E = 15 J
O k = 150 N/m and E = 3 J
O k = 200 N/m and E = 20 J
Ok = 200 N/m and E = 4 J
The solution of the equation of motion of a simple pendulum is given by: 8(1) = 0.2
Transcribed Image Text:A block of mass m = 1.5 kg is attached to a spring with a spring constant k. The position of the block as function of time is given by: x(t) = 0.2 cos(10t+n/2). Deduce the spring constant, k, and the total energy of the system: k = 150 N/m and E = 15 J O k = 150 N/m and E = 3 J O k = 200 N/m and E = 20 J Ok = 200 N/m and E = 4 J The solution of the equation of motion of a simple pendulum is given by: 8(1) = 0.2
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