Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
A spool of thin wire (with inner radius r= 0.40m, outer R= 0.55m, and moment of inertia Icm=0.79 Kg*m^2 pivots on a shaft. The wire is pulled down by a mass M = 1.35 kg. After falling a distance D=0.53 m, starting from rest, the mass has a speed of v=70.900 cm/s. Calculate the energy lost to friction during that time?

A spool of thin wire (with inner radius r= 0.40m, outer R= 0.55m, and moment of inertia Icm=0.79 Kg*m^2 pivots on a shaft. The wire is pulled down by a mass M = 1.35 kg. After falling a distance D=0.53 m, starting from rest, the mass has a speed of v=70.900 cm/s. Calculate the energy lost to friction during that time?

icon
Related questions
Question
A spool of thin wire (with inner radius r= 0.40m, outer R= 0.55m, and moment of inertia Icm=0.79 Kg*m^2 pivots on a shaft. The wire is pulled down by a mass M = 1.35 kg. After falling a distance D=0.53 m, starting from rest, the mass has a speed of v=70.900 cm/s. Calculate the energy lost to friction during that time?
Expert Solution
Given:
  • The inner radius of the wire is, r=0.40 m.
  • The outer radius of the wire is, R=0.55 m.
  • The moment of inertia is, I=0.79 kg·m2.
  • The mass of the object is, M=1.35 kg.
  • The height in which the object is falling, D=0.53 m.
  • The speed of the object is, v=70.9 cm/s=0.709 m/s.
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer