A spool of thin wire (with inner radius r= 0.40m, outer R= 0.55m, and moment of inertia Icm=0.79 Kg*m^2 pivots on a shaft. The wire is pulled down by a mass M = 1.35 kg. After falling a distance D=0.53 m, starting from rest, the mass has a speed of v=70.900 cm/s. Calculate the energy lost to friction during that time?
A spool of thin wire (with inner radius r= 0.40m, outer R= 0.55m, and moment of inertia Icm=0.79 Kg*m^2 pivots on a shaft. The wire is pulled down by a mass M = 1.35 kg. After falling a distance D=0.53 m, starting from rest, the mass has a speed of v=70.900 cm/s. Calculate the energy lost to friction during that time?
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A spool of thin wire (with inner radius r= 0.40m, outer R= 0.55m, and moment of inertia Icm=0.79 Kg*m^2 pivots on a shaft. The wire is pulled down by a mass M = 1.35 kg. After falling a distance D=0.53 m, starting from rest, the mass has a speed of v=70.900 cm/s. Calculate the energy lost to friction during that time?
Expert Solution
Given:
- The inner radius of the wire is,
- The outer radius of the wire is,
- The moment of inertia is,
- The mass of the object is,
- The height in which the object is falling,
- The speed of the object is,
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