A spherical rock of mass 4.0 kg is suspended from a cord. A steady horizontal breeze pushes the rock so that the cord makes a constant angle of 3.7° with the vertical. Find the tension in the cord. i N Hint

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### 4.11 Equilibrium Applications of Newton's Laws of Motion

**Problem Statement:**

A spherical rock of mass 4.0 kg is suspended from a cord. A steady horizontal breeze pushes the rock so that the cord makes a constant angle of 3.7° with the vertical. Find the tension in the cord.

**Hint:**

The hint section corresponds to an input field where students can request additional help or guidance on how to approach the problem.

**Solution:**

The provided space hints that an answer field where students are expected to enter their calculated tension (in Newtons) in the cord can be found right by the problem statement.

This problem involves applying Newton's Laws of Motion to achieve equilibrium. The following steps can be used to solve the problem:

1. **Identify Forces**: Determine the forces acting on the rock—gravitational force (weight) and the tension in the cord. The tension in the cord has both vertical and horizontal components.

2. **Vertical Component (T_y)**: The vertical component of the tension must balance the gravitational force:
   
   \( T_y = T \cos(3.7°) \)
   
   Where:
   - \( T \) is the tension in the cord.
   - \( T_y \) is the vertical component of the tension.
   - \( 3.7° \) is the angle the cord makes with the vertical.

3. **Gravitational Force**: The gravitational force acting on the rock (weight) is:
   
   \( W = mg \)
   
   Where:
   - \( m = 4.0 \) kg (mass of the rock)
   - \( g = 9.8 \) m/s² (acceleration due to gravity)
   
   \( W = 4.0 \times 9.8 \)
   \( W = 39.2 \) N

4. **Equating Forces**: Equate the vertical component of the tension to the gravitational force:
   
   \( T \cos(3.7°) = 39.2 \) N

5. **Solve for Tension (T)**: 
   
   \( T = \frac{39.2}{\cos(3.7°)} \)
   
   Use a calculator to find \( \cos(3.7°) \), and then solve for \( T \).

After following these steps, you will find
Transcribed Image Text:### 4.11 Equilibrium Applications of Newton's Laws of Motion **Problem Statement:** A spherical rock of mass 4.0 kg is suspended from a cord. A steady horizontal breeze pushes the rock so that the cord makes a constant angle of 3.7° with the vertical. Find the tension in the cord. **Hint:** The hint section corresponds to an input field where students can request additional help or guidance on how to approach the problem. **Solution:** The provided space hints that an answer field where students are expected to enter their calculated tension (in Newtons) in the cord can be found right by the problem statement. This problem involves applying Newton's Laws of Motion to achieve equilibrium. The following steps can be used to solve the problem: 1. **Identify Forces**: Determine the forces acting on the rock—gravitational force (weight) and the tension in the cord. The tension in the cord has both vertical and horizontal components. 2. **Vertical Component (T_y)**: The vertical component of the tension must balance the gravitational force: \( T_y = T \cos(3.7°) \) Where: - \( T \) is the tension in the cord. - \( T_y \) is the vertical component of the tension. - \( 3.7° \) is the angle the cord makes with the vertical. 3. **Gravitational Force**: The gravitational force acting on the rock (weight) is: \( W = mg \) Where: - \( m = 4.0 \) kg (mass of the rock) - \( g = 9.8 \) m/s² (acceleration due to gravity) \( W = 4.0 \times 9.8 \) \( W = 39.2 \) N 4. **Equating Forces**: Equate the vertical component of the tension to the gravitational force: \( T \cos(3.7°) = 39.2 \) N 5. **Solve for Tension (T)**: \( T = \frac{39.2}{\cos(3.7°)} \) Use a calculator to find \( \cos(3.7°) \), and then solve for \( T \). After following these steps, you will find
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