(a) Calculate the tension (in N) in a vertical strand of spiderweb if a spider of mass 7.00 x 10-5 kg hangs motionless on it. (Enter a number.) (b) Calculate the tension (in N) in a horizontal strand of spiderweb if the same spider sits motionless in the middle of it much like the tightrope walker in the figure. y 5.0⁰ x TR T₁ TA W -5.0° ↑ The strand sags at an angle of 15.0° below the horizontal. (Enter a number.) N Compare this with the tension in the vertical strand (find their ratio). (Enter a number.) (tension in horizontal strand)/(tension in vertical strand) =

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Newton’s Third Law of Motion

The horse pulls the cart and the cart pulls the horse in response as per Newton third law. So the big question is, “Don’t the two forces cancel each other? How does the cart accelerate?”