A spherical capacitor with charge, Q = 6.04 μC, has inner radius, 32.8 cm, and outer radius, 46.7 cm. (a) How much electric potential energy is stored in the capacitor? Uc = 0 X (b) What is the magnitude of the electric field midway between the two spheres? Emid = 0 V/m x (c) What is the energy density midway between the two spheres? J/m³ x UE=0
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A: The area of the plates: The separation between the plates: The voltage of the battery:
Q: A spherical capacitor with charge, Q = 6.04 μC, has inner radius, 32.8 cm, and outer radius, 46.7…
A: Given that:
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A: a) capacitance C = ε0Ad = 8.85 x 10-12x (2.0 x 10-4)1.7 x 10-3C = 1.04 x 10-12C = 1.04 PF
Q: An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by…
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Q: An air-filled parallel-plate capacitor has plates of area 2.40 cm2 separated by 2.50 mm. The…
A: Solution: Given: A = area of the plates = 2.40 cm2 = 2.40 x 10-4 m2 d = spacing between the plates…
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- A parallel plate capacitor is made from two aluminum foil sheets, each 3.8cm wide and 6.1 m long. Between the sheets is a Teflon strip of the same width and length that is 0.025mm thick. What is the energy stored in the capacitor when the charge on the capacitor is 30 uC?A parallel-plate capacitor has capacitance C0 = 8.00 pF when there is air between the plates. The separation between the plates is 1.20 mm. Express your answer with the appropriate units. Part A: What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates is not to exceed 3.00×104 V/m? Part B: A dielectric with K = 2.70 is inserted between the plates of the capacitor, completely filling the volume between the plates. Now what is the maximum magnitude of charge on each plate if the electric field between the plates is not to exceed 3.00×104 V/m?A capacitor consists of two large flat parallel plates. One plate has surface charge density 4.96 nC/m2 and the other has an equal but opposite surface charge density. The plates are spaced a distance 8.01 cm apart. Give the magnitude of the voltage (difference in electric potential) between the two plates. Answer in units of V.
- An air-filled parallel-plate capacitor has plates of area 2.80 cm separated by 1.80 mm. The capacitor is connected to a(n) 18.0 v battery. (a) Find the value of its capacitance. pF (b) What is the charge on the capacitor? pC (c) What is the magnitude of the uniform electric field between the plates? N/CRegarding the Earth and a cloud layer 650 m above the Earth as the "plates" of a capacitor, calculate the capacitance if the cloud layer has an area of 1.53 km2. If an electric field of 2.0 × 106 N/C makes the air breakdown and conduct electricity (lightning), what is the maximum charge the cloud can hold? εo = 8.85 x 10−12 F/mYou are given a parallel plate capacitor with plates having a rectangular area of 16.7 cm2 and a separation of 2.2 mm. The space between the plates is filled with a material having a dielectric constant κ = 1.8. Find the capacitance of this system.
- The electric field in a region of space has the components Ey = E₂ = 0 and Ex = (5.20 N/(C-m))x. Point A is on the y axis at y = 4.70 m, and point B is on the x axis at x = 5.30 m. What is the potential difference (in V) VB - VA?An air-filled parallel-plate capacitor has plates of area 2.90 cm? separated by 3.00 mm. The capacitor is connected to a(n) 13.0 V battery. (a) Find the value of its capacitance. pF (b) What is the charge on the capacitor? pC (c) What is the magnitude of the uniform electric field between the plates? N/C