A source injects an electron of speed v = 1.5 * 10^7 m/s into a uniform magnetic field of magnitude B = 1.0 * 10-3 T. The velocity of the electron makes an angle u = 10° with the direction of the magnetic field. Find the distance d from the point of injection at which the electron next crosses the field line that passes through the injection point.

Q: An oxygen nucleus (8 protons, 8 neutrons) moves at a velocity of 2.48 x 10^6 m/s in a direction…

A: Velocity, v = 2.48 x 10^6 m/s Radius, R = 3.44 cm = 3.44×10-2 mCharge, q = 8eMass of nucleus, m =…

Q: Problem 7: An alpha particle (consisting of two protons and two neutrons), traveling at a speed of…

A: Particle : Alpha particle Number of protons = 2 Number of neutrons = 2 Speed (v) = 1.4×105…

Q: J. find An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.275 T.…

A:

Q: a) Calculate the speed (vf) that the particle will have when it exits from between the parallel…

A: Given: mass m =1.23*10-26 kgcharge = 5e = 5*1.6*10-19 C = 8*10-19 C  (negative)potential V = 89132.5…

Q: Given y-z plane. An electron having velocity  v= −2.2×10^8 j m/s enters a uniform magnetic field of…

A: The expression for the required magnetic force is,

Q: Electrons starting from rest are accelerated through a potential difference of 210 V and fired into…

A: Given Data: Standard Data:

Q: A charged particle with speed v = 1 x 10 m/s enters a uniform magnetic field of B = 1.2 T. The…

A: Given: Charged particle with speed v=1×105 m/s enters magnetic field B=1.2 T            Angle makes…

Q: Protons having a kinetic energy of 3.10 MeV are moving in the positive x-direction and enter a…

A:

Q: At time t = 0, an electron with kinetic energy 16 keV moves through x = 0 in the positive direction…

A: GivenKinetic Energy of electron ,K.E=16 keVMagnitude of vertical component of Earth's magnetic…

Q: /s and is ejected southward entering a uniform magnetic field of unknown magnitude and direction. If…

A:

Q: An electron with an energy of 861 eV is moving in a straight path. What should be the magnitude of…

A: Write the expression for the kinetic energy and substitute the corresponding values to calculate the…

Q: At time t = 0, an electron with kinetic energy 11 keV moves through x = 0 in the positive direction…

A:

Q: A particle having mass m  = 2.80E-4 kg carries a negative charge q= −1.70E-6 C . The particle is…

A: A particle having mass m = 2.80E-4 kg carries a negative charge q = −1.70E-6 C . The particle is…

Q: a magnitude of 9.1 mT. If the speed of the electron is 1.50 \( \times \)107 m/s, determine the…

A: Mass of electron, m=9.11×10-31kg Charge on electron, q=1.6×10-19C Magnetic field strength,…

Q: The figure below shows the path of an electron in a region of uniform magnetic field B (into the…

A: The magnitude of the electric field, E=200 N/C The velocity of the electron, v=2×106 m/s The length…

Q: Will the particle travel Clockwise or Counterclockwise in the magnetic field? Explain how you…

A: The magnetic field is an invisible space around a magnetic object. A magnetic field is basically…

Q: kinetic energy 1.32 keV circles in

A: K.E. of electron is given by 1.32 KeV and radius of circle is r=0.309 m.

Q: Problem 255. Two points lying on the same lield line are separated by a distance XY = 1 = 10 cm in…

A:

Q: At time t = 0, an electron with kinetic energy 16 keV moves through x = 0 in the positive direction…

A: Given Kinetic Energy of the electron = 16 keV Magnetic field = 63.6 μ T To find out  Magnitude of…

Q: In the figure, an electron accelerated from rest through potential difference V₁=1.06 kV enters the…

A:

Q: A negatively charged ion with an excess electron moving with a velocity vx = 1.095 x103 m/s is…

A:

Q: A uniform magnetic field of 2.00×10¬³T is applied to put an electron into a circular orbit with…

A: Given that the value of uniform magnetic field and angular momentum. Then We have to determine the…

Q: A hypothetical charge 36pC with mass 72fg has a speed of 53 km/s and is ejected southward entering a…

A:

Q: A particle having mass m = 2.80E-4 kg carries a negative charge q= −1.70E-6 C . The particle is…

A: Mass of particle is Charge on particle is Velocity is in downward (-y)-direction.Magnetic field is…

Q: In the figure, an electron with an initial kinetic energy of 4.10 keV enters region 1 at time t = 0.…

A: Concept: The Formula for the Force due to Magnetic Field is, Fm=qv→×B→ Thus, qvB=mv2Rhere,v=qBRmNow,…

Q: At the instant an electron enters a uniform magnetic field of 0.500 T directed along the positive…

A: The centripetal force needed for the circular motion of the electron is supplied by the magnetic…

Q: An electron is accelerated by the action of a potential difference of 10 V and subsequently enters a…

A:

Q: y В 30 X

A: q = 1.00x10-8 C   v = 3.00x 104 m/s  B= 1T  M= 10-3 kg

Q: To better understand the Earth's climate history, you are using a mass spectrometer to distinguish…

A: The equation for the diameter D of a charged particle's circular path in a magnetic field can be…

Q: An electron of kinetic energy 1.78 keV circles in a plane perpendicular to a uniform magnetic field.…

A:

Q: Protons having a kinetic energy of 4.66 MeV (1 ev = 1.60 x 1019 )) are moving in the positive x…

A: In magnetic field proton follows circular path hence, radius of proton is as follows: r=mveB…

Q: A positively charged particle slides off a frictionless and smooth surface with initial X X X X x x…

A: When we have magnetic field in space that magnetic field apply a force on positive charge in upward…

Q: A particle having mass m  = 2.80E-4 kg carries a negative charge q= −1.70E-6 C . The particle is…

A: particle having mass m = 2.80E-4 kg  negative charge q= −1.70E-6 C . The particle is given an…

Q: A magnetic dipole with a dipole moment of magnitude 0.017 J/T is released from rest in a uniform…

A: Here is the step-by-step explanationWe will use the conservation of energy principle, to solve for…

Q: . The radius of the path

A: Given; Magnetic field B=0.2 T Alpha particles (m=6.7×10-27kg,  q=+2e)Potential difference = 6.7…

Q: particle having mass m = 2.80E-4 kg carries a negative charge q= −1.70E-6 C . The particle is given…

A: Mass of particle = 2.80x10-4 kgNegative charge q = - 1.70x10-6 CVelocity = 3.65x102 m/s.

Q: n alpha-particle (m = 6.64·10−27 kg; q = 3.2·10−19 C) travels in a circular path of radius 28 cm in…

A: Mass of alpha-particle m=6.64×10-27 kg Charge q=3.2×10-19C Radius of circular path r=28 cm=0.28 m…

Q: A 30.0-g metal ball having net charge Q = 5.50 µC is thrown out of a window horizontally north at a…

A:

Q: Problem 5: An electron (q= -e = -1.60 × 10-19 C and me = 9.11 × 10-31 kg) in a cathode-ray tube is…

A: Magnetic field strength is 0.0029TExplanation:Given data:-Solution:-

Q: Consider a particle that has a charge to mass ratio of Im/ql=6.7×10-8 kg/C. The particle enters a…

A: Given, m/q= 6.7*10-8 kg/c B=0.9 T

Q: A particle having mass m = 2.80E-4 kg carries a negative charge q= −1.70E-6 C . The particle is…

A: We will first write an expression for magnitude of the magnetic force on a charged particle moving…

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.