In the problem 8 of chapter 17 (attached photo), why are you using the speed of sound in air if the question specifies the submarine is in the ocean, thus, the sea water medium? Chapter 17, Problem 8PEA sonar echo returns to a submarine 1.20 s after being emitted. What is the distance to the object creating theecho? (Assume that the submarine is in me ocean. not in fresh water.)SAVEExpert Solution & AnswerTo determineDistance to the object creating the echoAnswer to Problem 8PEDistance to the object creating the echo is 206 mExplanation of SolutionGiven:Time of travel = T = 1.20 sec-1Speed of sound in air = Vair = 343 ms¯Distance of the object creating echo = dFormula Used:Distance of the object creating echo is given asd = (0.5)vairTCalculation:Distance of the object creating echo is given asd = (0.5)vairTInserting the valuesd = (0.5)(343)(1.20)d = 206 mConclusion:Thus, distance of the object creating the echo comes out to be 206 m

From the literature, it is found that velocity of sound in saline water is 1531 m/s at 250 C. It is…

Answered: A sonar echo returns to a submarine…

A sonar echo returns to a submarine 1.20 s after being emitted. What is the distance to the object creating the echo? (Assume that the submarine is in me ocean. not in fresh water.)

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In the problem 8 of chapter 17 (attached photo), why are you using the speed of sound in air if the question specifies the submarine is in the ocean, thus, the sea water medium?