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A solution of tartaric acid (H,CH,O) with a known concentration of 0.155 MHCHO, is titrated with a 0.425 M NAOH solution. How many mL of NaOH are required to reach the second equivalence point with a starting volume of 70.0 mL H.CH,O,, according to the following balanced chemical equation: H.C.HO, + 2 NaOH - Na CH,O, + 2 HO

A solution of tartaric acid (H,CH,O) with a known concentration of 0.155 MHCHO, is titrated with a 0.425 M NAOH solution. How many mL of NaOH are required to reach the second equivalence point with a starting volume of 70.0 mL H.CH,O,, according to the following balanced chemical equation: H.C.HO, + 2 NaOH - Na CH,O, + 2 HO

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter15: Acid-base Equilibria
Section: Chapter Questions
Problem 96AE: When a diprotic acid, H2A, is titrated with NaOH, the protons on the diprotic acid are generally...
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Question 20 of 20 Submit A solution of tartaric acid (H,C HO) with a known concentration of 0.155 MH.CHO, is titrated with a 0.425 M NaOH solution. How many mL of NaOH are required to reach the second equivalence point with a starting volume of 70.0 mL H,CHO, according to the following balanced chemical equation: н.Сно, + 2 NaOH - Na,C H,о, + 2 Но X STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 1 0.0217 51.1 0.155 1000 70.0 25.5 0.0511 5.11 x 10 12.8 0.001 2 0.425 mol NaOH g H̟C,H,O, mL NAOH MH,CH,O, mol H,C,H,O, L NAOH M NaOH g NaOH LH.C,H,O. mL H.C,H,O.
Transcribed Image Text:Question 20 of 20 Submit A solution of tartaric acid (H,C HO) with a known concentration of 0.155 MH.CHO, is titrated with a 0.425 M NaOH solution. How many mL of NaOH are required to reach the second equivalence point with a starting volume of 70.0 mL H,CHO, according to the following balanced chemical equation: н.Сно, + 2 NaOH - Na,C H,о, + 2 Но X STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 1 0.0217 51.1 0.155 1000 70.0 25.5 0.0511 5.11 x 10 12.8 0.001 2 0.425 mol NaOH g H̟C,H,O, mL NAOH MH,CH,O, mol H,C,H,O, L NAOH M NaOH g NaOH LH.C,H,O. mL H.C,H,O.
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