A sólution of g/L acrylamide in than is polymerized at /L isobutyryi peroxide (initiator) whose half life is 9.0 h at this temperature and efficiency in methanol is 0.3. For acrylamide, k,²/k= 22 L mol· s·l at 25°C and termination is by coupling alone. (a) What is the initial steady state rate of polymerization ? (b) Find the percentage conversion of monomers in the first 10 min of reaction in 1L of solution? Acrylamide H H C=C C-NH2 Hi Hint : Find the initial concentration of monomer in mol/L [M] =(100 g/L)/(Molecular weight of acrylamide) Given the half-life time of the initiator used. Find dissociation rate constant of the initiator. In(2). Half-life t/2= 1/2 fks R, = k, k, ka 0.693/K. %3D [M] 1/2 - In = 2 [M], ka

A sólution of g/L acrylamide in than is polymerized at /L isobutyryi peroxide (initiator) whose half life is 9.0 h at this temperature and efficiency in methanol is 0.3. For acrylamide, k,²/k= 22 L mol· s·l at 25°C and termination is by coupling alone. (a) What is the initial steady state rate of polymerization ? (b) Find the percentage conversion of monomers in the first 10 min of reaction in 1L of solution? Acrylamide H H C=C C-NH2 Hi Hint : Find the initial concentration of monomer in mol/L [M] =(100 g/L)/(Molecular weight of acrylamide) Given the half-life time of the initiator used. Find dissociation rate constant of the initiator. In(2). Half-life t/2= 1/2 fks R, = k, k, ka 0.693/K. %3D [M] 1/2 - In = 2 [M], ka

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Catalysis and Enzymatic Reactions

Catalysis is the kind of chemical reaction in which the rate (speed) of a reaction is enhanced by the catalyst which is not consumed during the process of reaction and afterward it is removed when the catalyst is not used to make up the impurity in the product. The enzymatic reaction is the reaction that is catalyzed via enzymes.

Lock And Key Model

The lock-and-key model is used to describe the catalytic enzyme activity, based on the interaction between enzyme and substrate. This model considers the lock as an enzyme and the key as a substrate to explain this model. The concept of how a unique distinct key only can have the access to open a particular lock resembles how the specific substrate can only fit into the particular active site of the enzyme. This is significant in understanding the intermolecular interaction between proteins and plays a vital role in drug interaction.

Question

A solution of 100 g/L acrylamide in methanol is polymerized at 25°C with 0.1 mol/L isobutyryl
peroxide (initiator) whose half life is 9.0 h at this temperature and efficiency in methanol is 0.3.
For acrylamide, k,?/k= 22 L mol-' s-l at 25°C and termination is by coupling alone.
(a) What is the initial steady state rate of polymerization ?
(b) Find the percentage conversion of monomers in the first 10 min of reaction in 1L of
2.5
solution?
Acrylamide
H
H
C-NH2
Hint :
Find the initial concentration of monomer in mol/L
[M] =(100 g/L)/(Molecular weight of acrylamide)
Given the half-life time of the initiator used. Find dissociation rate constant of the initiator.
In(2)
Half-life t/2=
kd
1/2
fks
[1)* [M]
k,
1/2
0.693/K.
R = k,
[M]
kp
2
1/2
- In-
%3D
[M],

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