A solution made with U.12 oles of a triprotic acid dissolved Dilowing AaS :Kal = 5.5e – 02; Ka2 = 9.2e – 05; Ka3 = 8.0e – 08; this solution was titrated with 1.330 M NaOH. Calculate the pH at the following points of the titration and the volume of base in mL needed to reach the final equivalence point:

Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter30: Nutrition
Section: Chapter Questions
Problem 30.68P
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solution made with 0.126 moles of a triprotic acid dissolved in 180 mL of solution has the following KA's... (rest in pic) please answer

A solution made with 0.126 moles of a triprotic acid dissolved in 180 mL of solution has the following Kas
:Kal = 5.5e – 02; Ka2 = 9.2e – 05; Ka3 = 8.0e – 08; this solution was titrated with 1.330 M NAOH.
Calculate the pH at the following points of the titration and the volume of base in mL needed to reach the
%3D
final equivalence point:
(Points A-G correspond to initial, half-way and equivalence points throughout the titration.)
A =
number (rtol=0.01, atol=1e-08)
B =
number (rtol=0.01, atol=1e-08)
C =
number (rtol=0.01, atol=1e-08)
55.0 mL
number (rtol=0.02, atol=1e-08)
%3D
D =
number (rtol=0.01, atol=1e-08)
E =
number (rtol=0.01, atol=1e-08)
120 mL
number (rtol=0.01, atol=1e-08)
F =
number (rtol=0.01, atol=1e-08)
G =
number (rtol=0.01, atol=1e-08)
Volume of base (mL)
number (rtol=0.01, atol=1e-08)
Transcribed Image Text:A solution made with 0.126 moles of a triprotic acid dissolved in 180 mL of solution has the following Kas :Kal = 5.5e – 02; Ka2 = 9.2e – 05; Ka3 = 8.0e – 08; this solution was titrated with 1.330 M NAOH. Calculate the pH at the following points of the titration and the volume of base in mL needed to reach the %3D final equivalence point: (Points A-G correspond to initial, half-way and equivalence points throughout the titration.) A = number (rtol=0.01, atol=1e-08) B = number (rtol=0.01, atol=1e-08) C = number (rtol=0.01, atol=1e-08) 55.0 mL number (rtol=0.02, atol=1e-08) %3D D = number (rtol=0.01, atol=1e-08) E = number (rtol=0.01, atol=1e-08) 120 mL number (rtol=0.01, atol=1e-08) F = number (rtol=0.01, atol=1e-08) G = number (rtol=0.01, atol=1e-08) Volume of base (mL) number (rtol=0.01, atol=1e-08)
G43-
HA?-/A-
EHA?-
pH
D
CH2A
H3A/H2A
H3A
V1
V2
V3
Vol. NaOH(aq) added
Transcribed Image Text:G43- HA?-/A- EHA?- pH D CH2A H3A/H2A H3A V1 V2 V3 Vol. NaOH(aq) added
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