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A solution contains 0.100 M Ce³", 1.00 × 104M Ce**, 1.00 × 10-4 M Mn2", 0.100 M MnO4, and 1.00 M HCIO4. For the following cell reaction, calculate E and AG at the given conditions. 6Co* (aq) + Mn²* (aq) + 4H20 (1) = sco" (aq) + MnO,' (aq) + 8H* (aq) -0.193 V and 93.1 kJ ) 0.23 V and 111 kJ ) 0.02 V and - 10 kJ ) -0.02 V and 10 kJ SHOW ALL WORK PLEASE AND DONT SKI ANY STEPS TY E° (Ce** /Ce*) = 1.70 V E° (MnO4-/Mn2*) = 1.507 V

A solution contains 0.100 M Ce³", 1.00 × 104M Ce**, 1.00 × 10-4 M Mn2", 0.100 M MnO4, and 1.00 M HCIO4. For the following cell reaction, calculate E and AG at the given conditions. 6Co* (aq) + Mn²* (aq) + 4H20 (1) = sco" (aq) + MnO,' (aq) + 8H* (aq) -0.193 V and 93.1 kJ ) 0.23 V and 111 kJ ) 0.02 V and - 10 kJ ) -0.02 V and 10 kJ SHOW ALL WORK PLEASE AND DONT SKI ANY STEPS TY E° (Ce** /Ce*) = 1.70 V E° (MnO4-/Mn2*) = 1.507 V

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A solution contains 0.100 M Ce³*, 1.00 × 104M Ce**, 1.00 × 10-4 M Mn2", 0.100 M MnO4, and 1.00 M HCIO4. For the following cell reaction, calculate E and AG at the given conditions. 5Ce* (aq) + Mn2* (aq) + 4H20 (1) = sCe* (aq) + Mno," (aq) + 8H* (aq) -0.193 V and 93.1 kJ ) 0.23 V and 111 kJ 0.02 V and -10 kJ ) -0.02 V and 10 kJ SHOW ALL WWORK PLEASE AND DONT SKIP ANY STEPS TY E° (Ce** /Ce3*) = 1.70 V E° (MnO4-/Mn2*) = 1.507 V
Transcribed Image Text:A solution contains 0.100 M Ce³*, 1.00 × 104M Ce**, 1.00 × 10-4 M Mn2", 0.100 M MnO4, and 1.00 M HCIO4. For the following cell reaction, calculate E and AG at the given conditions. 5Ce* (aq) + Mn2* (aq) + 4H20 (1) = sCe* (aq) + Mno," (aq) + 8H* (aq) -0.193 V and 93.1 kJ ) 0.23 V and 111 kJ 0.02 V and -10 kJ ) -0.02 V and 10 kJ SHOW ALL WWORK PLEASE AND DONT SKIP ANY STEPS TY E° (Ce** /Ce3*) = 1.70 V E° (MnO4-/Mn2*) = 1.507 V
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