A solution containing 0.20 M Pb²+ , 1.5 x 10-ó M Pb* , 1.5 × 10-6 M Mn²+ , 0.20 M MnO, , and 0.88 M HNO, was prepared. For this solution, the balanced reduction half-reactions and overall net reaction shown can occur. 5 [Pb*+ + 2e- = Pb²*] 2 [MnO, + 8 H* + 5e- Mn²+ + 4 H,Oj 5 Pb*+ + 2 Mn²+ + 8 H,0=5 Pb²+ + 2MNO, + 16H* E = 1.690 V E = 1.507 V Determine E, AG', and K for this reaction. V AG = J
Ionic Equilibrium
Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibrium is established between the ions and unionized species in a system. Understanding the concept of ionic equilibrium is very important to answer the questions related to certain chemical reactions in chemistry.
Arrhenius Acid
Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.
Bronsted Lowry Base In Inorganic Chemistry
Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.
A solution containing 0.200.20 M Pb2+Pb2+ , 1.5×10−61.5×10−6 M Pb4+Pb4+ , 1.5×10−61.5×10−6 M Mn2+Mn2+ , 0.200.20 M MnO−4MnO4− , and 0.880.88 M HNO3HNO3 was prepared. For this solution, the balanced reduction half‑reactions and overall net reaction shown can occur.
| 5[Pb4++2e−↽−−⇀Pb2+]5[Pb4++2e−↽−−⇀Pb2+] | ?∘+=1.690 VE+°=1.690 V |
| 2[MnO−4+8H++5e−↽−−⇀Mn2++4H2O]2[MnO4−+8H++5e−↽−−⇀Mn2++4H2O] | ?∘−=1.507 VE−°=1.507 V |
| 5Pb4++2Mn2++8H2O↽−−⇀5Pb2++2MnO−4+16H+5Pb4++2Mn2++8H2O↽−−⇀5Pb2++2MnO4−+16H+ |
![A solution containing 0.20 M Pb²+, 1.5 x 10-6 M Pb* , 1.5 × 10-6 M Mn²+ , 0.20 M MnO, , and 0.88 M HNO, was
prepared. For this solution, the balanced reduction half-reactions and overall net reaction shown can occur.
5 [Pb*+ + 2e- Pb2+]
2 [MnO, + 8 H* + 5e- Mn2+ + 4 H, O]
5 Pb*+ + 2 Mn?+ + 8 H,0=5 Pb2+ + 2 MnO, + 16 H*
E: = 1.690 V
E: = 1.507 V
Determine Ee, AG', and K for this reaction.
V
AG' =
K =
Calculate the value for the cell potential, Ecell, and the free energy, AG, for the given conditions.
Ecell =
AG =
J
Calculate the value of Ecell for this system at equilibrium.
Eçell
V
Determine the pH at which the given concentrations of Pb2+, Pb*+, Mn2+, and MnO, would be at equilibrium.
pH =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8d1b31df-0f67-47d9-936e-b5ce55c8aa00%2Fec3d7895-a85d-43d4-b0ea-f326e46971c1%2Fkf0zkho_processed.png&w=3840&q=75)
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