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A solid plastic ball has a radius of 6.0 cm and has a charge of +3.o nC ( in
nano-Coulombs) that is uniformly distributed throughout its volume. Imagine there is
a proton being held 1.5 cm away from the surface of the solid plastic ball, and then the
proton is released. The proton will accelerate away from the ball, as we know, due to
the repulsive electric force. Assuming the ball doesn't move, how fast is the proton
moving when it is 5.5 cm away from the surface of the ball?

Expert Solution

Step 1

Given:

The radius of the plastic ball is 6 cm and the total charge distributed on it is +3.0 nC.

The proton is held at a distance of 1.5 cm.

The proton is repelled and it is moving, the kinetic energy is to be found at 5.5 cm.

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