A solid object floating in water. Part of the object's volume is under the surface (denoted as Vunder). The mass of the solid object is m = 3.9530 kg and its total volume is V = 6.70x10-3 m³. The density of water is pw = 1000.0 kg/m³, and the magnitude of the gravitational acceleration is g = 9.80 m/s² Part A - Find Vunder, the solid object's volume that is UNDER the water surface. If you enter a regular number, keep 6 digits after the decimal point, in m³ If you use scientific notation such as 1.234 -10-³, keep 3 digits after the decimal point. Vunder = Submit Provide Feedback ■ ΑΣΦ Request Answer ? m³

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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A solid object floating in water. Part of the object's
volume is under the surface (denoted as Vunder).
The mass of the solid object is m = 3.9530 kg and
its total volume is V = 6.70×10-³ m³ . The density
3
of water is pw = 1000.0 kg/m³, and the
magnitude of the gravitational acceleration is g =
9.80 m/s²
Part A - Find Vunder, the solid object's volume that is UNDER the water surface.
If you enter a regular number, keep 6 digits after the decimal point, m³
If you use scientific notation such as 1.234-10-3, keep 3 digits after the decimal point.
Vunder
Submit
Provide Feedback
- ΑΣΦ
Request Answer
?
m³
Transcribed Image Text:A solid object floating in water. Part of the object's volume is under the surface (denoted as Vunder). The mass of the solid object is m = 3.9530 kg and its total volume is V = 6.70×10-³ m³ . The density 3 of water is pw = 1000.0 kg/m³, and the magnitude of the gravitational acceleration is g = 9.80 m/s² Part A - Find Vunder, the solid object's volume that is UNDER the water surface. If you enter a regular number, keep 6 digits after the decimal point, m³ If you use scientific notation such as 1.234-10-3, keep 3 digits after the decimal point. Vunder Submit Provide Feedback - ΑΣΦ Request Answer ? m³
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