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A solid cylindrical link of yield strength, S, is loaded axially by equal and opposite forces, F. The diameter of the shaft is d. The nominal values are all uncertain by the following percentages: The yield strength by ± 5 percent. The force by + 10 percent. The diameter by ±8 percent. What safety factor is required to avoid failure?

A solid cylindrical link of yield strength, S, is loaded axially by equal and opposite forces, F. The diameter of the shaft is d. The nominal values are all uncertain by the following percentages: The yield strength by ± 5 percent. The force by + 10 percent. The diameter by ±8 percent. What safety factor is required to avoid failure?

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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A solid cylindrical link of yield strength, S, is loaded axially by equal and opposite forces, F. The diameter of the shaft is d. The nominal values are all uncertain by the following percentages: The yield strength by + 5 percent. The force by ± 10 percent. The diameter by + 8 percent. What safety factor is required to avoid failure?
Transcribed Image Text:A solid cylindrical link of yield strength, S, is loaded axially by equal and opposite forces, F. The diameter of the shaft is d. The nominal values are all uncertain by the following percentages: The yield strength by + 5 percent. The force by ± 10 percent. The diameter by + 8 percent. What safety factor is required to avoid failure?
Expert Solution
Step 1

The factor of safety is defined as the ratio of the yield stress to the working stress.

FOS=σyieldσworking

here, FOS is the factor of safety

σyield is the yield stress, 

σworking is the working stress,

The value of the factor of safety plays an important role to avoid failure.

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