A solid conducting sphere of radius 5.00 cm carries a net charge. To find the value of the charge, you measure the potential difference VAB = VA – VB between point A, which is 8.00 cm from the center of the sphere, and point B, which is a distance r from the center of the sphere. You repeat these measurements for several values of r 8 cm When 8 cm When

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Could you please explain how to do this? I'm not sure how to use the slope (-18 Vm) to solve the problem.  Thanks!

I Review | Constants
Part A
A solid conducting sphere of radius 5.00 cm carries a
net charge. To find the value of the charge, you
measure the potential difference VAB = VA – VB
between point A, which is 8.00 cm from the center of
the sphere, and point B, which is a distance r from
the center of the sphere. You repeat these
measurements for several values of r > 8 cm. When
you plot your data as VAB versus 1/r, the values lie
close to a straight line with slope -18.0 V · m.
АВ
What does your data give for the net charge on the sphere?
Express your answer with the appropriate units.
μΑ
?
q =
Value
C
Submit
Request Answer
Transcribed Image Text:I Review | Constants Part A A solid conducting sphere of radius 5.00 cm carries a net charge. To find the value of the charge, you measure the potential difference VAB = VA – VB between point A, which is 8.00 cm from the center of the sphere, and point B, which is a distance r from the center of the sphere. You repeat these measurements for several values of r > 8 cm. When you plot your data as VAB versus 1/r, the values lie close to a straight line with slope -18.0 V · m. АВ What does your data give for the net charge on the sphere? Express your answer with the appropriate units. μΑ ? q = Value C Submit Request Answer
Expert Solution
Step 1

We know that the Potential due to the solid sphere is given by 

We know that the formula of the  potential is 

VA= kqrVA= kq0.08and VB= kqr

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