A solid ball of radius rh has a uniform charge density e. Part A What is the magnitude of the electric field E (r) at a distance r> r, from the center of the ball? Express your answer in terms of p, rb, r, and €o. > View Available Hint(s) E (r) = Part B What is the magnitude of the electric field E (r) at a distance r < rh from the center of the ball? Express your answer in terms of p, r, rb, and €o. • View Available Hint(s) ΑΣφ E (r) =
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- Part A A conducting sphere has a net charge of Q = 8nC and a radius of r= 10cm. What is the surface charge density? να ΑΣφ nC/m2 Submit Request Answerplease answer all parts and explanation.Part A A closed surface encloses a net charge of 3.10 μC . What is the net electric flux through the surface? Express your answer in newton-meters squared per coulomb. %0 ΑΣΦ Submit Request Answer Part B Submit ? If the electric flux through a closed surface is determined to be 2.20 Nm²/C, how much charge is enclosed by the surface? Express your answer in coulombs. IVE ΑΣΦ Request Answer N.m²/C ? C Pearson
- I Rew A spherically symmetric charge distribution produces the electric field E =( 5700 r2)r N/C, where r is in m. Part A What is the electric field strength at r = 19.0 cm ? ? N/C Submit Request Answer Part B What is the electric flux through a 38.0-cm-diameter spherical surface that is concentric with the charge distribution? Nm2/C Submit Request Answer Part C How much charge is inside this 38.0-cm-diameter spherical surface? Cneed help on part A, C, Dplease provide reasoning and diagram as well. Thank you!
- Part A Use Coulomb's law to determine the magnitude of the electric field at points A and B in (Figure 1) due to the two positive charges (Q = 4.9 µC ) shown. Suppose that a = 5.9 cm. Determine the magnitude of the electric field at A. Express your answer to two significant figures and include the appropriate units. ? EA = Value Units Submit Request Answer Figure < 1 of 1 Part B Determine the angle between the direction of the electric field at point A and the positive x-direction. B A Express your answer using two significant figures. +Q +Q OA = a a 2a Submit Request Answer▼ Part A The electric field strength 29 cm from the center of a uniformly charged, hollow metal sphere is 11,000 N/C. The sphere is 8.4 cm in diameter, and all the charge is on the surface. What is the magnitude of the surface charge density in nC/cm2 ? Express your answer in nanocoulombs per square centimeter. Hνα ΑΣφ nC/cm2 Submit Request Answer Provide FeedbackA E The picture shows the field lines of a nonuniform electric field and five points A to E in the field. Consider the following statements. Which one is true? This electric field may be due to a negatively charged object located to the left. A positive point charge placed at point C will feel a stronger electric force than at point D. OThe electric field strengths at points B and C are the same because they are on the same field line. OThe electric field strengths at points A and D are both zero because there are no electric field lines on them. A negative point charge placed at point C will feel an electric force pointing to the right.
- Charge Q is distributed uniformly throughout the volume of an insulating sphere of radius R = 4.00 cm. At a distance of r = 8.00 cm from the center of the sphere, the electric field due to the charge distribution has magnitude 740 N/C. Part A What is the volume charge density for the sphere? Express your answer with the appropriate units. HA p = Value Units Part B What is the magnitude of the electric field at a distance of 2.00 cm from the sphere's center? Express your answer with the appropriate units. E= Value UnitsTwo point charges are located on a horizontal line as Shown in diagram on the right. The first small circle Represents the charge Q1 the left and small circle on right Q2 . In the middle between the two charges is point P. a) Find the net electric field due to the 2 charges at point P by finding the magnitude and direction of each one if Q1 =3μC and Q2 =5μC and distance between charges = 50 cm.