A solid aluminum alloy [E=69 GPa; α=23.6×10−6/C∘] rod (1) is attached rigidly to a solid brass [E=115 GPa; α=18.7×10−6/C∘] rod (2), as shown in the figure. The compound rod is subjected to a tensile load of P=5.3 kN. The diameter of each rod is 11 mm. The rods lengths are L1=507 mm and L2=705 mm. Compute the change in temperature required to produce zero horizontal deflection at end C of the compound rod.
A solid aluminum alloy [E=69 GPa; α=23.6×10−6/C∘] rod (1) is attached rigidly to a solid brass [E=115 GPa; α=18.7×10−6/C∘] rod (2), as shown in the figure. The compound rod is subjected to a tensile load of P=5.3 kN. The diameter of each rod is 11 mm. The rods lengths are L1=507 mm and L2=705 mm. Compute the change in temperature required to produce zero horizontal deflection at end C of the compound rod.
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Chapter1: Units, Trigonometry. And Vectors
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A solid aluminum alloy [E=69 GPa; α=23.6×10−6/C∘] rod (1) is attached rigidly to a solid brass [E=115 GPa; α=18.7×10−6/C∘] rod (2), as shown in the figure. The compound rod is subjected to a tensile load of P=5.3 kN. The diameter of each rod is 11 mm. The rods lengths are L1=507 mm and L2=705 mm. Compute the change in temperature required to produce zero horizontal deflection at end C of the compound rod.
![A solid aluminum alloy [E = 69 GPa; a = 23.6 x 10-6/°C] rod (1) is attached rigidly to a solid brass [E = 115 GPa; a = 18.7 x 10-6°C] rod (2), as shown in the figure. The compound rod is subjected to a tensile load of P = 5.3 kN. The
diameter of each rod is 11 mm. The rods lengths are L₁ = 507 mm and L₂ = 705 mm. Compute the change in temperature required to produce zero horizontal deflection at end C of the compound rod.
L₁
Part 1
F₁ =
F₂ =
Part 2
What are the internal forces F₁ and F₂ in rods (1) and (2), respectively? Use the sign convention for internal axial forces discussed in Section 5.3.
kN
A =
kN
Determine the cross-sectional area for the rods.
(1) B
mm²
12₂
(2)
P](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbbb16848-0151-4811-b617-402fad34b898%2F46373c90-0c78-423d-b8a3-c0dabb9a26fc%2Fzk981n_processed.png&w=3840&q=75)
Transcribed Image Text:A solid aluminum alloy [E = 69 GPa; a = 23.6 x 10-6/°C] rod (1) is attached rigidly to a solid brass [E = 115 GPa; a = 18.7 x 10-6°C] rod (2), as shown in the figure. The compound rod is subjected to a tensile load of P = 5.3 kN. The
diameter of each rod is 11 mm. The rods lengths are L₁ = 507 mm and L₂ = 705 mm. Compute the change in temperature required to produce zero horizontal deflection at end C of the compound rod.
L₁
Part 1
F₁ =
F₂ =
Part 2
What are the internal forces F₁ and F₂ in rods (1) and (2), respectively? Use the sign convention for internal axial forces discussed in Section 5.3.
kN
A =
kN
Determine the cross-sectional area for the rods.
(1) B
mm²
12₂
(2)
P
![Part 3
If there were no temperature change, what would be the elongations S₁,p and $2,p of rods (1) and (2), respectively, due to the load P?
$₁.p =
82.p =
Part 4
UCP =
If there were no temperature change, what would be the magnitude of the horizontal deflection at end C of the compound rod due to load P?
Part 5
mm
mm
mm
°C
Compute the change in temperature required to produce zero horizontal deflection at end C of the compound rod. Enter a positive value for a temperature increase, or a negative value for a temperature decrease.
AT =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbbb16848-0151-4811-b617-402fad34b898%2F46373c90-0c78-423d-b8a3-c0dabb9a26fc%2Fx4wp94f_processed.png&w=3840&q=75)
Transcribed Image Text:Part 3
If there were no temperature change, what would be the elongations S₁,p and $2,p of rods (1) and (2), respectively, due to the load P?
$₁.p =
82.p =
Part 4
UCP =
If there were no temperature change, what would be the magnitude of the horizontal deflection at end C of the compound rod due to load P?
Part 5
mm
mm
mm
°C
Compute the change in temperature required to produce zero horizontal deflection at end C of the compound rod. Enter a positive value for a temperature increase, or a negative value for a temperature decrease.
AT =
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