Steel construction beams, with an industry designation of "W12 x 25," have a weight of 25 pounds per foot. A new business in town has hired you to place its sign on a 4.0 m long steel beam of this type. The design calls for the beam to extend outward horizontally from the front brick wall, as shown in the figure. It is to be held in place by a 5.0-m-long steel cable. The cable is attached to one end of the beam and to the wall above the point at which the beam is in contact with the wall. During an initial stage of construction, the beam is not to be bolted to the wall, but to be held in place solely by friction. 5.0 m 4.0 m Tipler & Mosca, Physics for Scientists and Engineers, 6e 2008 W.H. Freeman and Company What is the minimum coefficient of friction µs between the beam and the wall for the beam to remain in static equilibrium? What is the tension T in the cable in this case? Mg = T = N

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Steel construction beams, with an industry designation of "W12 × 25," have a weight of 25 pounds per foot. A new business in town has hired you to place its sign on a 4.0 m long steel beam of this type. The design calls for the beam to extend outward horizontally from the front brick wall, as shown in the figure. It is to be held in place by a 5.0-m-long steel cable. The cable is attached to one end of the beam and to the wall above the point at which the beam is in contact with the wall. During an initial stage of construction, the beam is not to be bolted to the wall, but to be held in place solely by friction.

*Diagram Description:*
The diagram shows a brick wall with a horizontal steel beam extending 4.0 m outwards. A diagonal steel cable, 5.0 m in length, connects the end of the beam to the wall above the beam.

*Questions:*
1. What is the minimum coefficient of friction (μₛ) between the beam and the wall for the beam to remain in static equilibrium?
   - μₛ = [Blank space for answer]

2. What is the tension (T) in the cable in this case?
   - T = [Blank space for answer] N

*Reference:*
Tipler & Mosca, *Physics for Scientists and Engineers, 6e* © 2008 W.H. Freeman and Company
Transcribed Image Text:Steel construction beams, with an industry designation of "W12 × 25," have a weight of 25 pounds per foot. A new business in town has hired you to place its sign on a 4.0 m long steel beam of this type. The design calls for the beam to extend outward horizontally from the front brick wall, as shown in the figure. It is to be held in place by a 5.0-m-long steel cable. The cable is attached to one end of the beam and to the wall above the point at which the beam is in contact with the wall. During an initial stage of construction, the beam is not to be bolted to the wall, but to be held in place solely by friction. *Diagram Description:* The diagram shows a brick wall with a horizontal steel beam extending 4.0 m outwards. A diagonal steel cable, 5.0 m in length, connects the end of the beam to the wall above the beam. *Questions:* 1. What is the minimum coefficient of friction (μₛ) between the beam and the wall for the beam to remain in static equilibrium? - μₛ = [Blank space for answer] 2. What is the tension (T) in the cable in this case? - T = [Blank space for answer] N *Reference:* Tipler & Mosca, *Physics for Scientists and Engineers, 6e* © 2008 W.H. Freeman and Company
A steel wire of length 1.40 m and diameter 1.00 mm is joined to an aluminum wire of identical dimensions to make a composite wire of length 2.80 m.

What is the resulting change in length ΔL of this composite wire if an object with a mass of 5.00 kg is hung vertically from one of its ends? (Neglect any effect the masses of two wires have on the changes in their lengths.)

ΔL = [Input box showing the value 1.751]

Status: Incorrect

Unit: mm
Transcribed Image Text:A steel wire of length 1.40 m and diameter 1.00 mm is joined to an aluminum wire of identical dimensions to make a composite wire of length 2.80 m. What is the resulting change in length ΔL of this composite wire if an object with a mass of 5.00 kg is hung vertically from one of its ends? (Neglect any effect the masses of two wires have on the changes in their lengths.) ΔL = [Input box showing the value 1.751] Status: Incorrect Unit: mm
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