A solenoid that is 91.4 cm long has a cross-sectional area of 15.0 cm2. There are 1000 turns of wire carrying a current of 6.74 A. (a) Calculate the energy density of the magnetic field inside the solenoid.
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A: Given: w =1.8 cm =1.8*10-2 mt = 1.0 mm =1.0 *10-3 mB=1.2 TI=15 A∆V=1.02 μV=1.02*10-6 V
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A: Magnetic field strength at the center of coil having N number of turns is given by as B= u°NI/(2r)
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Q: solenoid whose length is L = 50 cm. 3 cm in radius and has 500 turns. This solenoid is flowed by a…
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A: B=μ0NILB is magnetic fieldN is number of turnsI currentL is length of…
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Q: The above figure shows the cross sections of two wires carrying equal magnitude currents of 10 A but…
A: Magnitude of currents are I1=I2=10 A Distance between the wires are d= 0.5 m
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A: Given: B=0.707T l=40cm r=1.5cm
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- Activity 2 In a rectangular coordinate system a positive point charge q = 6.00 x 10 C is placed at the point = an identical point charge is placed at x = the electric field at the following points: (a) the origin; (b) x = 0.300 m. y = 0; (c) x - 0.150 m. y = I = 0. y = 0. 200 m. + 0.150 m. y = 0, and - 0, 150 m. y = 0. Find the x- and y-components, the magnitude, and the direction of - 0.400 m; (d)A solenoid of length 2.00 cm and radius 0.750 cm has 49 turns. If the wire of the solenoid has 1.95 amps of current, what is the magnitude of the magnetic field inside the solenoid? magnitude of the magnetic field: T Ignoring the weak magnetic field outside the solenoid, find the magnetic energy density inside the solenoid. magnetic energy density: J/m3 What is the total magnetic energy inside the solenoid? total magnetic energy: JSuppose you wish to produce a 2-T magnetic field in a toroid with an iron core for which magnetic susceptibility is x=3 x 10³. The toroid has a mean radius of 18 cm and is wound with 600 turns. Hint с a. What current is required to produce this magnetic field in the iron core? Current of A is needed. b. For comparison, what current is required to produce the same magnetic field in an air-filled toroid of same geometry? Current of While it is not always practical to have region of magnetic field filled with ferromagnetic materials, this dramatic increase in strength of magnetic field produced is useful in some applications you will see in upcoming chapters. Submit Question 4 A is needed for toroid with no iron core. % Search or type URL 5 MacBook Pro < 6 A 6 7 * 8 ( 9
- A solenoid of length 2.50 cm and radius 0.750 cm has 33 turns. If the wire of the solenoid has 1.25 amps of current, what is the magnitude of the magnetic field inside the solenoid? magnitude of the magnetic field: 2.07 x10-3 Ignoring the weak magnetic field outside the solenoid, find the magnetic energy density inside the solenoid. magnetic energy density: 1.70 J/m³ What is the total magnetic energy inside the solenoid? 3.19 x10¬6 total magnetic energy: J IncorrectA solenoid that is 92.1 cm long has a cross-sectional area of 19.7 cm2. There are 1240 turns of wire carrying a current of 5.79 A. (a) Calculate the energy density of the magnetic field inside the solenoid. (b) Find the total energy in joules stored in the magnetic field there (neglect end effects).In an electric motor, a coil with 100 turns of radius 2.0 cm can rotate between the poles of a magnet. The magnetic field magnitude is 0.20 T. When the current through the coil is 50.0 mA, what is the maximum torque that the motor can deliver?
- How much energy is stored in the magnetic field of a 20.0-cm-long solenoid that has 156 turns and a radius of 0.950 cm and carries a current of 1.65 A?A given toroidal coil has 1000 turns. Calculate the magnetic field at a point on a circle of radius 1.30 m inside the coil when the current I = 2.9 × 105 A.A 59.0 cm -long solenoid 1.35 cm in diameter is to produce a field of 0.395 mT at its center. How much current should the solenoid carry if it has 790 turns of wire?