A soil layer consists of 4 meters of sand underlying 5 meters of clay. The water table is naturally located at the rock bed under the soil strata but rose by 6 meters due to a recent storm. Further, capillary action is expected to de- velop due to the nature of the soil in question. Compute the effective stresses at the end of expected capillary ac- tion, at the end of the water table, at the interface of the clay and sand and finally at the bottom of the soil strata. Pertinent soil properties are as follows:
A soil layer consists of 4 meters of sand underlying 5 meters of clay. The water table is naturally located at the rock bed under the soil strata but rose by 6 meters due to a recent storm. Further, capillary action is expected to de- velop due to the nature of the soil in question. Compute the effective stresses at the end of expected capillary ac- tion, at the end of the water table, at the interface of the clay and sand and finally at the bottom of the soil strata. Pertinent soil properties are as follows:
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question #3
Transcribed Image Text:1. Consider Figure FTR 1 (Taken from Geotechnical Engineer-
ing Design, Ming Xiao, strictly for educational purposes)
shown. If the specific gravity of the soils are respectively
from top to bottom 2.6, 2.7 and 2.73, estimate the effec-
tive stresses at the mid thickness of each layer.
2. Still considering Figure FTR 1, estimate the additional stress-
es induced by the footing on the mid thickness of each
layer using both 2-1 approximation and graphical method
as proposed by Boussinesq.
3. A soil layer consists of 4 meters of sand underlying 5 meters
of clay. The water table is naturally located at the rock
bed under the soil strata but rose by 6 meters due to a
recent storm. Further, capillary action is expected to de-
velop due to the nature of the soil in question. Compute
the effective stresses at the end of expected capillary ac-
tion, at the end of the water table, at the interface of the
Q = 900 kN
Ground surface
D; = 1 m
Ground water table
Lx B = 3m x 2m
eo = 0.5, c = 0.35, c, = 0.06, o' = 75 kN/m2
H = 1m
H =9 m
eo = 0.48, c. = 0.33, c, = 0.05, o'= 100 kN/m2
H = 2m
eo = 0.45, c = 0.30, c, = 0.05, o= 180 kN/m2
H3 = 6m
clay and sand and finally at the bottom of the soil strata.
Pertinent soil properties are as follows:
Figure FTR 1
Average S, Capil-
lary Zone
G,
e
D10
Clay
2.71
0.98
0.0125
25
55%
Sand
2.74
0.93
N.A.
N.A.
N.A.
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