A soft drink bottler is interested in the smooth operation of the machine used to fill cans. In particular, you want the standard deviation of the filling process to be less than 0.2 fluid ounces; otherwise, there will be a higher than tolerable percentage of cans that will not be completely full. Assume that the fill volume is approximately normally distributed. A random sample of 20 cans results in a variance of S ^ 2 = 0.0225 (ounces) ^ 2. The image shows the creation of a 95% confidence interval Create an upper 95% confidence interval
A soft drink bottler is interested in the smooth operation of the machine used to fill cans. In particular, you want the standard deviation of the filling process to be less than 0.2 fluid ounces; otherwise, there will be a higher than tolerable percentage of cans that will not be completely full. Assume that the fill volume is approximately normally distributed. A random sample of 20 cans results in a variance of S ^ 2 = 0.0225 (ounces) ^ 2. The image shows the creation of a 95% confidence interval Create an upper 95% confidence interval
MATLAB: An Introduction with Applications
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Author:Amos Gilat
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A soft drink bottler is interested in the smooth operation of the machine used to fill cans. In particular, you want the standard deviation of the filling process to be less than 0.2 fluid ounces; otherwise, there will be a higher than tolerable percentage of cans that will not be completely full.
Assume that the fill volume is approximately
The image shows the creation of a 95% confidence interval
Create an upper 95% confidence interval

Transcribed Image Text:2
X0.025“ = 32.8523 para v = 19
X0.975 = 8.9065 para v = 19
(n – 1)S²
(п — 1)52
-
< σ<
2
Xa,?
X1-«/,?
(20 – 1)(0.0225)
(20 – 1)(0.0225)
32.8523
8.9065
0.01301 < o² < 0.047999
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