A soda straw is stuck into water at an angle of 36° to the vertical. Looking straight down, what does the angle of the submerged portion of the straw to the vertical appear to be? ANS: 44°
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I already know the answer to this practice problem, and it is shown is the image. I do not know how to get to the answer though, so seeing the steps and equations would be much appreciated.
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- Consider a convex lens having a thickness d whose sides have radii of curvature R1 and R2. a. Find the 2x2 matrix describing this lensb. What is the change in focal length for the case where the two radii equal R and d =0.1R, compared to the case where the lens thickness is neglected?A person is standing a distance d = 1.35 m away from a mirror, which is m = 0.870 m above the ground, as shown in Figure 1. Light hits their foot, reflects off of the mirror, and enters their eye (this is how they see the reflection of their foot!). How tall are they? (Measure their height h from the ground to their eye, and don't worry about the small distance from their eye to the top of their head, which we do not have enough information to determine).The vertical distance between eye level and the ground for a certain swimmer, who is standing upright, is 1.55 m. If the swimmer is standing 2.00 m from the edge of a 2.50-m-deep swimming pool, how far from the base of the pool will the swimmer be able to see a coin that is at the bottom of the pool? The swimmer is represented by the upward directed arrow in the diagram, and the distance between the base of the pool and the coin is “d”. The index of refraction of water is 1.33. a. 1.55 m b. 0.950 m c. 1.85 m d. 2.15 m e. 1.25 m
- M1.3 please answer all problems and also write out all steps and reasoning. The second image shows the correct answers.An object that is 5.0 cm high is placed 20.0 cm from a bi-convex lens (a positive, focusing lens) with a focus of 10.0 cm. Calculate the position of the image. O-6.7 cm O-20 cm O 20.0 cm O 15.0 cm O 10.0 cmFind the components of vtot along the x and y axes in Figure 3.25, where θ = 21.0° and vtot = 5.48 m/s.vtot, x = _____ m/svtot, y = _____ m/s I'm not really sure how to do this problem. I got x = 5.1 and y = 2.01, but this is incorrect.