A sociologist wants to construct a 95% confidence interval for the proportion of children aged 8-12 living in New York who own a smartphone.   A survey by the National Consumers League estimated the nationwide proportion to be 0.56 and the margin of error for a 95% confidence interval for the proportion is 0.0213.     Find the confidence interval.  Round your answer to nearest ten-thousandth if necessary.   (e.g. 0.13436 would be entered as 0.1344) Lower  Upper

Q: A 93.32% Cl is given as (2.5, 3.5). From this information, find a 95% confidence interval (yes, this…

A: The provided information is as follows:The 93.32% confidence interval is (2.5,3.5).

Q: na survey, 25 people were asked how much they spent on their child's last birthday gift. The results…

A: Given data,

Q: You may need to use the appropriate appendix table technology to answer this question. A 95%…

A: Assume that μ is the population mean.

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…

A: Given: Let n represents the number of parents of children surveyed; that is; n=1035. Let p^…

Q: Consider a sample of 100 people and subsequently a confidence interval calculated from the sample.…

A: The formula for calculating confidence interval is as follow:

Q: If n = 220,p = 0.4,then what will be the 87.4% confidence interval for the population proportion?

A:

Q: Believe it or not, there are some people who dont think that Duke will win the NCAA tournament this…

A: Obtain the 90% Confidence Interval for the IQ of DDs.   The 90% Confidence Interval for the IQ of…

Q: Suppose that the a college wants to have an idea of the average SAT score of the incoming freshman…

A: The confidence level is 0.90, the standard deviation is 310 and margin of error E is 50.

Q: interval at a 95% confidence level. Give your answers to one decimal place. Interpret your…

A: Given : Sample Size, n = 18 Sample Mean, x̄ = 35 sample standard…

Q: We would like to know: "What percentage of college students drink alcohol every day?" In a random…

A: Given that, N=500 X=75

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…

A:

Q: Given a sample size of 400 with a mean of 80 and the population standard deviation is found to be 35…

A: We have given that,  Sample mean (x̄) = 80, population standard deviation (σ) = 35 and sample size…

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…

A: No of parents surveyed n = 1091 Point estimate p-hat = 0.74 Margin of error E = ± 0.04

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…

A: Let x be the number of people who are willing to take a second or part-time job. It is given that…

Q: If n=13, (x-bar)=48, and s=12, construct a confidence interval at a 95% confidence level. Assume the…

A: Mean = 48Standard deviation = 12Sample size = 13

Q: p'= α %4 || Margin of Error: E We are 87% confident that the proportion of Americans who feel that…

A:

Q: Beth wants to determine a 90% confidence interval for the proportion of high school students in a…

A: We have given that,  Population proportion (p) = 0.57, margin of error (E) = 0.04 and confidence…

Q: If n = 370 and p=0.31p, construct a 90% confidence interval. This should be rounded to three decimal…

A:

Q: A magazine article conducted a survey of 1000 people in Washington State and found that 26% of the…

A:

Q: Kim wants to determine a 80 % confidence interval for the true proportion ? of high school students…

A:

Q: You plan to conduct a survey to find out the proportion of students who enjoy taking classes…

A: Given  The margin of error is given as m=0.02 At a 90% confidence interval, α=0.1 As the proportion…

Q: If n=540 and (p-hat) = 0.13, construct a 99% confidence interval. Give your answers to three…

A: We have given that,  Sample size (n) = 540  Sample proportion (p-hat) = 0.13 Then,  We will find the…

Q: one with a 95% confidence level and the other with a 99.7% confidence level. Which interval is…

A: Confidence interval is probability, which refers that population parameter will fall within set of…

Q: An economist wants to estimate the mean per capita income (in thousands of dollars) for a major city…

A: Given, Sample size = 719 Sample mean = 23.7 Population standard deviation = 9.7   Since the…

Q: If α = 0.05, then what is the confidence level?

A: Given: α = 0.05   we know that, Confidence level+ α = 1

Q: In a survey, 17 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: A confidence interval was constructed to approximate a population proportion. The interval was from…

A: We have given that,  Let p̂ represents the sample proportion and E represents the margin of error,…

Q: 10. You want to estimate the proportion of all college students who traveled during spring break.…

A: Let X be the number of students reported travelling during spring break and n be the sample size.…

Q: Thelma and Louise are each attempting to estimate the proportion of adults who enjoy listening to…

A: Given that.  p=0.29 C.I for Thelma's=(0.242 , 0.338) C.I for Louise's=(0.237 , 0.323)

Q: In a survey, 25 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: A 95% confidence interval is constructed in order to estimate the proportion of all adults who are…

A: We have given a 95% confidence interval to estimate the proportion of all left-handed…

Q: If n=240 and X = 192, construct a 90% confidence interval. Enter your answer as an open-interval…

A: 1. The given values are n=240,x=192. The proportion of x is, p^=xn=192240=0.8 Computation of…

Q: In a survey, 14 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: Suppose you calculate a 95% confidence interval for a proportion to to be: 0.39 to 0.78. Determine…

A: Given,   Lower bound = 0.39​ Upper bound = 0.78   Here, we use to determine the margin of error.

Q: We would like to know: "What percentage of college students drink alcohol every day?" In a random…

A:

Q: If the alpha level is .05, then the confidence level is ?

A: Given: alpha = 0.05 confidence level / significant level = 1 - alpha

Q: You will need your z and t charts for this  Death penalty: A group claims that the overall feelings…

A: The question is about confidence interval.Given :No. of interviewed people ( n ) = 643No. of people…

Q: In a survey, 15 people were asked how much they spent on their child's last birthday gift. The…

A: The sample mean is 32 and standard deviation is 14.

Q: f n=19, sample mean=50, and s =8, construct a confidence interval at a 99% confidence level. Assume…

A:

Q: A few years ago, noon bicycle traffic past a busy section of campus had a mean of $\mu$ = 300.  To…

A: The t-test is used when the population standard deviation is unknown. It may also be used for…

Q: To construct a 95% Confidence Interval, we have to find the margin of error (ME), and we can use the…

A: From the provided information, Confidence level = 95% Standard error (SE) = 0.049 The z value at 95%…

Q: a sample of 25 automobiles shows that the mean price was $20,500 with standard deviation of $2,500.…

A: Givensample size = n = 25Mean price = $20,500Standard deviation = $2500 The distribution is normal.…

Q: Using an ? = 0.04, a confidence interval for a population proportion is determined to be 0.55 to…

A: Answer  Given  level of significance [α] =0.04 a confidence interval for a population proportion is…

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a…

A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.