A soccer player kicks a 0.4 kg ball from rest towards the opposing team's net. The ball has a velocity of 24 m/s the instant after being kicked, and the player's foot is in contact with the ball for 0.30 s. What is the average force exerted on the ball? 64 N 16 N O 80 N O 32 N 0.03 N
A soccer player kicks a 0.4 kg ball from rest towards the opposing team's net. The ball has a velocity of 24 m/s the instant after being kicked, and the player's foot is in contact with the ball for 0.30 s. What is the average force exerted on the ball? 64 N 16 N O 80 N O 32 N 0.03 N
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem Statement**
A soccer player kicks a 0.4 kg ball from rest towards the opposing team’s net. The ball has a velocity of 24 m/s the instant after being kicked, and the player’s foot is in contact with the ball for 0.30 s. What is the average force exerted on the ball?
**Answer Options**
- 64 N
- 16 N
- 80 N
- 32 N
- 0.03 N
**Explanation**
To find the average force exerted on the ball, we use the formula derived from Newton's second law, which connects force, mass, and acceleration:
\[ F = \frac{\Delta p}{\Delta t} \]
Where:
- \( \Delta p \) is the change in momentum
- \( \Delta t \) is the time during which the change occurs
**Steps:**
1. Calculate the change in momentum (\( \Delta p \)):
- Initial momentum = 0 (since the ball starts from rest)
- Final momentum = mass × final velocity = 0.4 kg × 24 m/s = 9.6 kg·m/s
- \(\Delta p = 9.6 \, \text{kg·m/s} - 0 = 9.6 \, \text{kg·m/s}\)
2. Calculate the average force:
- \[ F = \frac{\Delta p}{\Delta t} = \frac{9.6 \, \text{kg·m/s}}{0.30 \, \text{s}} = 32 \, \text{N} \]
Therefore, the average force exerted on the ball is **32 N**.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F51fe66f0-6d16-409f-b5db-308d38c717ff%2Fa99ab29c-01f7-4049-b684-842d1a6e1896%2F3p9tjzm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement**
A soccer player kicks a 0.4 kg ball from rest towards the opposing team’s net. The ball has a velocity of 24 m/s the instant after being kicked, and the player’s foot is in contact with the ball for 0.30 s. What is the average force exerted on the ball?
**Answer Options**
- 64 N
- 16 N
- 80 N
- 32 N
- 0.03 N
**Explanation**
To find the average force exerted on the ball, we use the formula derived from Newton's second law, which connects force, mass, and acceleration:
\[ F = \frac{\Delta p}{\Delta t} \]
Where:
- \( \Delta p \) is the change in momentum
- \( \Delta t \) is the time during which the change occurs
**Steps:**
1. Calculate the change in momentum (\( \Delta p \)):
- Initial momentum = 0 (since the ball starts from rest)
- Final momentum = mass × final velocity = 0.4 kg × 24 m/s = 9.6 kg·m/s
- \(\Delta p = 9.6 \, \text{kg·m/s} - 0 = 9.6 \, \text{kg·m/s}\)
2. Calculate the average force:
- \[ F = \frac{\Delta p}{\Delta t} = \frac{9.6 \, \text{kg·m/s}}{0.30 \, \text{s}} = 32 \, \text{N} \]
Therefore, the average force exerted on the ball is **32 N**.
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