A soap film supported by a vertical loop has settled and is thinner at the top than at the bottom. Light of frequency f = 7.5 x 10¹4 Hz is incident on the film (n =) at essentially normal incidence.
A soap film supported by a vertical loop has settled and is thinner at the top than at the bottom. Light of frequency f = 7.5 x 10¹4 Hz is incident on the film (n =) at essentially normal incidence.
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Please explain in detail each question as instructed in problem
Transcribed Image Text:**Educational Transcription: Soap Film Interference Analysis**
A soap film, supported by a vertical loop, has settled such that it is thinner at the top than at the bottom. Light with a frequency \( f = 7.5 \times 10^{14} \) Hz is incident on this film with a refractive index \( n = \frac{4}{3} \) at essentially normal incidence.
**Diagram Explanation:**
- The diagram is a cross-sectional side view (not to scale) of the soap film.
- Three observers, labeled as C, A, and B, are positioned on the left side of the soap film.
- The soap film is depicted with varying thickness:
- The "Thinnest part of soap film" is at the top.
- The "Thickest part of soap film" is at the bottom.
**Questions:**
1. **Observer C's Perspective:**
- Observer C is looking at the thinnest part of the film, where it is extremely thin.
- Question: To this observer, would the film appear bright or dark? Explain your reasoning.
2. **Thickest Part Observation:**
- The thickness of the film at the bottom is 1650 nm.
- Question: Would this part of the film appear bright, dark, or in between? Explain.
These questions involve concepts related to thin film interference, where the thickness of the film and the wavelength of incident light influence the observed brightness.
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