A small round ball of mass 3 kg hangs by a thin rope from the roof of a train carriage like a pendulum. The train moves off from the platform with a constant acceleration of ‘a’ m/s2 This causes the round ball to effectively swing backward and adopt a position with the rope at an angle theta ( θ = 25degree) to the vertical. It stays in this position due to constant acceleration. By applying Newton’s second law: a) Derive an expression for the acceleration of the train Consider the horizontal and vertical components of the tension force in the rope, your expression will be in terms of the acceleration ‘a’ and the gravitational acceleration g (9.81 m/s2 ), and the angle ( θ ). b) Calculate the acceleration of the train, m/s2 ? c) Calculate the tension, N in the rope.
A small round ball of mass 3 kg hangs by a thin rope from the roof of a train carriage like a pendulum. The train moves off from the platform with a constant acceleration of ‘a’ m/s2 This causes the round ball to effectively swing backward and adopt a position with the rope at an angle theta ( θ = 25degree) to the vertical. It stays in this position due to constant acceleration. By applying Newton’s second law: a) Derive an expression for the acceleration of the train Consider the horizontal and vertical components of the tension force in the rope, your expression will be in terms of the acceleration ‘a’ and the gravitational acceleration g (9.81 m/s2 ), and the angle ( θ ). b) Calculate the acceleration of the train, m/s2 ? c) Calculate the tension, N in the rope.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
A small round ball of mass 3 kg hangs by a thin rope from the roof of a train carriage like a
pendulum. The train moves off from the platform with a constant acceleration of ‘a’ m/s2 This
causes the round ball to effectively swing backward and adopt a position with the rope at an angle theta ( θ = 25degree) to the vertical. It stays in this position due to constant acceleration. By applying
Newton’s second law:
a) Derive an expression for the acceleration of the train Consider the horizontal and
vertical components of the tension force in the rope, your expression will be in terms
of the acceleration ‘a’ and the gravitational acceleration g (9.81 m/s2
), and the angle
( θ ).
b) Calculate the acceleration of the train, m/s2
?
c) Calculate the tension, N in the rope.
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