A particle at rest leaves the origin with its velocity increasing with time according to v(t) = 2.3t m/s. At 5.0 s, the particle's velocity starts decreasing according to [11.5-1.3(t - 5.0)] m/s. This decrease continues until t = 11.0 s, after which the particle's velocity remains constant at 3.7 m/s. (a) What is the acceleration of the particle as a function of time? (Use the following as necessary: t. Do not use other variables, substitute numeric values. Assume that a is in m/s2 and t is in seconds. Do not include units in your answer.) a(t) = t< 5.0 s units of B 5.0 s < t < 11.0 s t> 11.0 s (b) What is the position of the particle (in m) at t = 2.0 s, t = 7.0 s, and t = 12.0 s? x(2.0 s) = m x(7.0 s) = m x(12.0 s) = m Between t = 0 and t = to, a rocket moves straight upward with an acceleration given by a(t) = A - Bt¹/2, where A and B are constants. (Assume a is in m/s².) (a) If x is in meters and t is in seconds, what are the units of A and B? (Use the following as necessary: m and s.) units of A = (b) If the rocket starts from rest, how does the velocity vary between t = 0 and t = to? (Enter the rocket's velocity as a function of time. Use the following as necessary: A, B, and t.) v(t) = (c) If its initial position is zero, what is the rocket's position as a function of time during this same time interval? (Use the following as necessary: A, B, and t.)
A particle at rest leaves the origin with its velocity increasing with time according to v(t) = 2.3t m/s. At 5.0 s, the particle's velocity starts decreasing according to [11.5-1.3(t - 5.0)] m/s. This decrease continues until t = 11.0 s, after which the particle's velocity remains constant at 3.7 m/s. (a) What is the acceleration of the particle as a function of time? (Use the following as necessary: t. Do not use other variables, substitute numeric values. Assume that a is in m/s2 and t is in seconds. Do not include units in your answer.) a(t) = t< 5.0 s units of B 5.0 s < t < 11.0 s t> 11.0 s (b) What is the position of the particle (in m) at t = 2.0 s, t = 7.0 s, and t = 12.0 s? x(2.0 s) = m x(7.0 s) = m x(12.0 s) = m Between t = 0 and t = to, a rocket moves straight upward with an acceleration given by a(t) = A - Bt¹/2, where A and B are constants. (Assume a is in m/s².) (a) If x is in meters and t is in seconds, what are the units of A and B? (Use the following as necessary: m and s.) units of A = (b) If the rocket starts from rest, how does the velocity vary between t = 0 and t = to? (Enter the rocket's velocity as a function of time. Use the following as necessary: A, B, and t.) v(t) = (c) If its initial position is zero, what is the rocket's position as a function of time during this same time interval? (Use the following as necessary: A, B, and t.)
College Physics
11th Edition
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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![A particle at rest leaves the origin with its velocity increasing with time according to v(t) = 2.3t m/s. At 5.0 s, the particle's velocity starts decreasing according to [11.5 - 1.3(t5.0)] m/s. This decrease continues until t = 11.0 s, after which the particle's
velocity remains constant at 3.7 m/s.
(a) What is the acceleration of the particle as a function of time? (Use the following as necessary: t. Do not use other variables, substitute numeric values. Assume that a is in m/s² and t is in seconds. Do not include units in your answer.)
a(t) =
units of A =
t < 5.0 s
units of B =
5.0 s < t < 11.0 s
(b) What is the position of the particle (in m) at t = 2.0 s, t = 7.0 s, and t = 12.0 s?
x(2.0 s) =
x(7.0 s) =
x(12.0 s) =
Between t = 0 and t = to, a rocket moves straight upward with an acceleration given by a(t) = A - Bt¹/2, where A and B are constants. (Assume a is in m/s².)
(a) If x is in meters and t is in seconds, what are the units of A and B? (Use the following as necessary: m and s.)
t> 11.0 s
m
m
m
(b) If the rocket starts from rest, how does the velocity vary between t = 0 and t = to? (Enter the rocket's velocity as a function of time. Use the following as necessary: A, B, and t.)
v(t) =
(c) If its initial position is zero, what is the rocket's position as a function of time during this same time interval? (Use the following as necessary: A, B, and t.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fea8d789b-97df-4158-8f36-f808034efdd2%2Fd3020c91-f4f1-4b8a-8a73-751027f4cb2f%2Fda3oi0a_processed.png&w=3840&q=75)
Transcribed Image Text:A particle at rest leaves the origin with its velocity increasing with time according to v(t) = 2.3t m/s. At 5.0 s, the particle's velocity starts decreasing according to [11.5 - 1.3(t5.0)] m/s. This decrease continues until t = 11.0 s, after which the particle's
velocity remains constant at 3.7 m/s.
(a) What is the acceleration of the particle as a function of time? (Use the following as necessary: t. Do not use other variables, substitute numeric values. Assume that a is in m/s² and t is in seconds. Do not include units in your answer.)
a(t) =
units of A =
t < 5.0 s
units of B =
5.0 s < t < 11.0 s
(b) What is the position of the particle (in m) at t = 2.0 s, t = 7.0 s, and t = 12.0 s?
x(2.0 s) =
x(7.0 s) =
x(12.0 s) =
Between t = 0 and t = to, a rocket moves straight upward with an acceleration given by a(t) = A - Bt¹/2, where A and B are constants. (Assume a is in m/s².)
(a) If x is in meters and t is in seconds, what are the units of A and B? (Use the following as necessary: m and s.)
t> 11.0 s
m
m
m
(b) If the rocket starts from rest, how does the velocity vary between t = 0 and t = to? (Enter the rocket's velocity as a function of time. Use the following as necessary: A, B, and t.)
v(t) =
(c) If its initial position is zero, what is the rocket's position as a function of time during this same time interval? (Use the following as necessary: A, B, and t.)
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