A small, rigid object carries positive and negative 3.00 nC charges. It is oriented so that the positive charge has coordinates (-1.20 mm, 1.40 mm) and the negative charge is at the point (1.30 mm, -1.30 mm). (a) Find the electric dipole moment of the object. -7.5e-12 ✔ C.mî+ 8.1e-12 Comj (b) The object is placed in an electric field E = (7.80 x 10³ 1-4.90 x 103 ) N/C.Find the torque acting on the object. -1.9e-8 X Your response differs from the correct answer by more than 10%. Double check your calculations. N. m k (c) Find the potential energy of the object-field system when the object is in this orientation. 8✓ (d) Assuming the orientation of the object can change, find the difference between the maximum and the minimum potential energies of the system.

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter24: Electric Fields
Section24.5: Electric Field Of A Continuous Charge Distribution
Problem 24.6CE: a. Figure 24.22A shows a rod of length L and radius R with excess positive charge Q. The excess...
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A small, rigid object carries positive and negative 3.00 nC charges. It is oriented so that the positive charge has coordinates (-1.20 mm, 1.40 mm) and the negative charge is at the point (1.30
mm, -1.30 mm).
(a) Find the electric dipole moment of the object.
-7.5e-12
Cmî+ 8.1e-12
C.mĵ
(b) The object is placed in an electric field E = (7.80 x 10³ î - 4.90 x 10³ ĵ) N/C. Find the torque acting on the object.
X
-1.9e-8
Your response differs from the correct answer by more than 10%. Double check your calculations. N . m k
(c) Find the potential energy of the object-field system when the object is in this orientation.
J
|♥
(d) Assuming the orientation of the object can change, find the difference between the maximum and the minimum potential energies of the system.
J
Transcribed Image Text:A small, rigid object carries positive and negative 3.00 nC charges. It is oriented so that the positive charge has coordinates (-1.20 mm, 1.40 mm) and the negative charge is at the point (1.30 mm, -1.30 mm). (a) Find the electric dipole moment of the object. -7.5e-12 Cmî+ 8.1e-12 C.mĵ (b) The object is placed in an electric field E = (7.80 x 10³ î - 4.90 x 10³ ĵ) N/C. Find the torque acting on the object. X -1.9e-8 Your response differs from the correct answer by more than 10%. Double check your calculations. N . m k (c) Find the potential energy of the object-field system when the object is in this orientation. J |♥ (d) Assuming the orientation of the object can change, find the difference between the maximum and the minimum potential energies of the system. J
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