Consider the following. 0.500 mm 60.0 (a) Red blood cells often become charged and can be treated as point charges. Healthy red blood cells are negatively charged, but unhealthy cells (due to the presence of a bacteria, for example) can become positively charged. In the figure, three red blood cells are oriented such that they are located on the corners of an equilateral triangle. The red blood cell charges are A = 1.80 pC, B = 7.10 pC, and C = -4.40 pC. Given these charges, what would the magnitude and direction of the electric field be at cell A? (1 pC = 1 x 10-12 C.)

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Chapter1: Units, Trigonometry. And Vectors
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Consider the following.
0.500 mm
60.0
(a) Red blood cells often become charged and can be treated as point charges. Healthy red blood cells are negatively charged, but
unhealthy cells (due to the presence of a bacteria, for example) can become positively charged. In the figure, three red blood cells
are oriented such that they are located on the corners of an equilateral triangle. The red blood cell charges are
A = 1.80 pC, B = 7.10 pC, and C = -4.40 pC. Given these charges, what would the magnitude and direction of the electric field
be at cell A? (1 pC = 1 x 10-12 C.)
magnitude
N/C
direction
° counterclockwise from the +x-axis
(b) If the charge of cell A were doubled, how would the electric field at cell A change?
The magnitude of the field would be doubled.
The magnitude of the field would be halved.
Does the electric field at cell A include the electric field generated by cell A?The field would be unchanged.
O The magnitude of the field would be quadrupled.
Transcribed Image Text:Consider the following. 0.500 mm 60.0 (a) Red blood cells often become charged and can be treated as point charges. Healthy red blood cells are negatively charged, but unhealthy cells (due to the presence of a bacteria, for example) can become positively charged. In the figure, three red blood cells are oriented such that they are located on the corners of an equilateral triangle. The red blood cell charges are A = 1.80 pC, B = 7.10 pC, and C = -4.40 pC. Given these charges, what would the magnitude and direction of the electric field be at cell A? (1 pC = 1 x 10-12 C.) magnitude N/C direction ° counterclockwise from the +x-axis (b) If the charge of cell A were doubled, how would the electric field at cell A change? The magnitude of the field would be doubled. The magnitude of the field would be halved. Does the electric field at cell A include the electric field generated by cell A?The field would be unchanged. O The magnitude of the field would be quadrupled.
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