A small rectangular coil of 6 by 4 mm is placed in the middle of a solenoid of 40 mm length having 100 turns and carrying current of 9.5 A, see sketch below (assume that the area of the coil is in the plane of the sketch ). Calculate the force on each side of the rectangular coil due to magnetic field of the solenoid given that the current of 2.0 A is passed through the small coil. Give vour answer in micro-Newtons (uN. 1 uN = 10-6 N). Take uo = 4T X 10-7 H/m.
A small rectangular coil of 6 by 4 mm is placed in the middle of a solenoid of 40 mm length having 100 turns and carrying current of 9.5 A, see sketch below (assume that the area of the coil is in the plane of the sketch ). Calculate the force on each side of the rectangular coil due to magnetic field of the solenoid given that the current of 2.0 A is passed through the small coil. Give vour answer in micro-Newtons (uN. 1 uN = 10-6 N). Take uo = 4T X 10-7 H/m.
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![A small rectangular coil of 6 by 4 mm is placed in the middle of a solenoid of 40 mm length having 100 turns and carrying
current of 9.5 A, see sketch below (assume that the area of the coil is in the plane of the sketch ). Calculate the force on each
side of the rectangular coil due to magnetic field of the solenoid given that the current of 2.0 A is passed through the small
coil. Give your answer in micro-Newtons (uN, 1 µN = 106 N). Take Ho = 4x × 10-' H/m.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffce7d1cf-fd94-437a-96d6-f04c8e223f13%2F7b0f40a8-db0d-4f46-945d-a0c9bb1c7257%2Fzyxi17p_processed.png&w=3840&q=75)
Transcribed Image Text:A small rectangular coil of 6 by 4 mm is placed in the middle of a solenoid of 40 mm length having 100 turns and carrying
current of 9.5 A, see sketch below (assume that the area of the coil is in the plane of the sketch ). Calculate the force on each
side of the rectangular coil due to magnetic field of the solenoid given that the current of 2.0 A is passed through the small
coil. Give your answer in micro-Newtons (uN, 1 µN = 106 N). Take Ho = 4x × 10-' H/m.
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