A "long" solenoid of length 1.61 m has radius 7.24 cm, 6,303 turns and carries current 94.7. Now a small circular coil with 595 turns, radius 4.62 mm and carrying current 63.8 A is placed inside the coil so the planes of the two coils are at right angles to each other. Find the magnitude of the torque, in N-m, felt by the small coil.

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**Problem Statement:**

A "long" solenoid of length 1.61 m has a radius of 7.24 cm and 6,303 turns, carrying a current of 94.7 A. Now, a small circular coil with 595 turns, a radius of 4.62 mm, and carrying a current of 63.8 A is placed inside the solenoid. The planes of the two coils are at right angles to each other. Determine the magnitude of the torque, in N-m, experienced by the small coil.

**Solution Explanation:**

To solve this problem, use the following concepts:

1. **Magnetic Field Inside a Solenoid:**
   The magnetic field \( B \) inside a long solenoid is given by:
   \[
   B = \mu_0 \cdot n \cdot I
   \]
   where \(\mu_0\) is the permeability of free space (\(4\pi \times 10^{-7} \, \text{T}\cdot\text{m/A}\)), \(n\) is the number of turns per unit length, and \(I\) is the current.

2. **Torque on a Coil in a Magnetic Field:**
   The torque \(\tau\) on a current-carrying coil in a magnetic field is given by:
   \[
   \tau = n \cdot I \cdot A \cdot B \cdot \sin(\theta)
   \]
   where \(n\) is the number of turns, \(I\) is the current in the coil, \(A\) is the area of the coil, \(B\) is the magnetic field, and \(\theta\) is the angle between the magnetic field and the normal to the plane of the coil (\(90^\circ\) in this case, so \(\sin(\theta) = 1\)).

3. **Area of a Circular Coil:**
   The area \(A\) of a circular coil with radius \(r\) is:
   \[
   A = \pi r^2
   \]

Insert the given values and calculate the torque acting on the small coil.
Transcribed Image Text:**Problem Statement:** A "long" solenoid of length 1.61 m has a radius of 7.24 cm and 6,303 turns, carrying a current of 94.7 A. Now, a small circular coil with 595 turns, a radius of 4.62 mm, and carrying a current of 63.8 A is placed inside the solenoid. The planes of the two coils are at right angles to each other. Determine the magnitude of the torque, in N-m, experienced by the small coil. **Solution Explanation:** To solve this problem, use the following concepts: 1. **Magnetic Field Inside a Solenoid:** The magnetic field \( B \) inside a long solenoid is given by: \[ B = \mu_0 \cdot n \cdot I \] where \(\mu_0\) is the permeability of free space (\(4\pi \times 10^{-7} \, \text{T}\cdot\text{m/A}\)), \(n\) is the number of turns per unit length, and \(I\) is the current. 2. **Torque on a Coil in a Magnetic Field:** The torque \(\tau\) on a current-carrying coil in a magnetic field is given by: \[ \tau = n \cdot I \cdot A \cdot B \cdot \sin(\theta) \] where \(n\) is the number of turns, \(I\) is the current in the coil, \(A\) is the area of the coil, \(B\) is the magnetic field, and \(\theta\) is the angle between the magnetic field and the normal to the plane of the coil (\(90^\circ\) in this case, so \(\sin(\theta) = 1\)). 3. **Area of a Circular Coil:** The area \(A\) of a circular coil with radius \(r\) is: \[ A = \pi r^2 \] Insert the given values and calculate the torque acting on the small coil.
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