A small cannonball with mass 4 kilograms is shot vertically upward with an initial velocity of 190 meters per second. If the air resistance is assumed to be directly proportional to the speed of the cannonball, a differential equation modeling the projectile velocity is dv m = mg mg - kv dt Assume that k = 0.0025, and use g = -9.8 meters/second². Solve the differential equation for the velocity v(t). Don't forget to include the initial condition. v(t) = = Integrate the velocity to obtain the height h(t) as a function of time. Assume the cannonball is launched from ground level at t = 0. h(t) = Find the maximum height reached by the cannonball. Max height = meters

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