A small box of mass m1 is sitting on a board of mass m2 and length L. The coefficient of kinetic friction between the board and the horizontal floor is μk . The coefficient of static friction between the board and the box is μs. At this moment, the board slides to the right along the surface, while the box does not slide on the board. What is the maximum magnitude of the force F pulling the board so that the box does not slip on the board?
A small box of mass m1 is sitting on a board of mass m2 and length L. The coefficient of kinetic friction between the board and the horizontal floor is μk . The coefficient of static friction between the board and the box is μs. At this moment, the board slides to the right along the surface, while the box does not slide on the board. What is the maximum magnitude of the force F pulling the board so that the box does not slip on the board?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A small box of mass m1 is sitting on a board of mass m2 and length L. The
coefficient of kinetic friction between the board and the horizontal floor is μk . The coefficient of
static friction between the board and the box is μs.
At this moment, the board slides to the right along the surface, while the box does not slide on
the board. What is the maximum magnitude of the force F pulling the board so that the box
does not slip on the board?
coefficient of kinetic friction between the board and the horizontal floor is μk . The coefficient of
static friction between the board and the box is μs.
At this moment, the board slides to the right along the surface, while the box does not slide on
the board. What is the maximum magnitude of the force F pulling the board so that the box
does not slip on the board?
THE ANSWER IS =(?? + ??)(?1 + ?2)?
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Can you help with the ending of part 3 why do we add back in the mu of static friction I don't get why it is added in?
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