A skydiver jumps out of a helicopter at 6000 feet above the ground. As he descends, the force of air resistance acting upon him continually changes. The free- body diagrams below represent the magnitude and direction of the two forces acting upon the skydiver at six positions during his fall. K 6000 feet (Sch C Fgrav-900 N 3000 feet m/s/s Fair 1100 N ga-900 N a= 5500 feet Fair 200 N gav 900 N 2900 feet m/s/s Fair-1500 N gav 900 N m/s/s 4500 feet Fair-900 N 1500 feet 900 N m/s/s Fair-900 N 900 N m/s/s m/s/s For each diagram (altitude) apply Newton's second law (Fnet = m*a) to determine the acceleration value. Be sure to note the direction of acceleration as well. (Hint: To determine the sky diver's mass, consider what you have learned about the link between gravitational force and mass.) You may use 10 m/s/s as an approximation for g (gravitational acceleration).
A skydiver jumps out of a helicopter at 6000 feet above the ground. As he descends, the force of air resistance acting upon him continually changes. The free- body diagrams below represent the magnitude and direction of the two forces acting upon the skydiver at six positions during his fall. K 6000 feet (Sch C Fgrav-900 N 3000 feet m/s/s Fair 1100 N ga-900 N a= 5500 feet Fair 200 N gav 900 N 2900 feet m/s/s Fair-1500 N gav 900 N m/s/s 4500 feet Fair-900 N 1500 feet 900 N m/s/s Fair-900 N 900 N m/s/s m/s/s For each diagram (altitude) apply Newton's second law (Fnet = m*a) to determine the acceleration value. Be sure to note the direction of acceleration as well. (Hint: To determine the sky diver's mass, consider what you have learned about the link between gravitational force and mass.) You may use 10 m/s/s as an approximation for g (gravitational acceleration).
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:A skydiver jumps out of a helicopter at
6000 feet above the ground. As he
descends, the force of air resistance acting
upon him continually changes. The free-
body diagrams below represent the
magnitude and direction of the two forces
acting upon the skydiver at six positions
during his fall.
MC
6000 feet
CR
C
Fguv
3000 feet
-900 N
m/s/s
Fair=1100 N
grav=900 N
m/s/s
a=
5500 feet
Fair 200 N
Fay=900 N
2900 feet
m/s/s a=
Faiz-1500 N
900 N
4500 feet
Fair= 900 N
v-900 N
1500 feet
m/s/s
Fair-900 N
gav 900 N
m/s/s a=
For each diagram (altitude) apply Newton's
second law (Fnet = m*a) to determine the
acceleration value. Be sure to note the
direction of acceleration as well. (Hint: To
determine the sky diver's mass, consider
what you have learned about the link
between gravitational force and mass.)
m/s/s
You may use 10 m/s/s as an approximation
for g (gravitational acceleration).
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