(a) Sketch the graph of the given function. t, 0 7 f(t) 7 6 5 4. 3 • 2 10 t (b) Express f(t) in terms of the unit step function uc(t). f(t)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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**(a) Sketch the Graph of the Given Function**

The function \( f(t) \) is defined piecewise as follows:

\[
f(t) = 
\begin{cases} 
t, & 0 \leq t < 2 \\
2, & 2 \leq t < 5 \\
-t + 7, & 5 \leq t < 7 \\
0, & t \geq 7 
\end{cases}
\]

**Graph Explanation:**

- **Segment 1 \( (0 \leq t < 2): \)** The function \( f(t) = t \) is a linear function, depicted as a straight line starting from the origin (0, 0) and ending at (2, 2). The point at (2, 2) is an open circle, indicating that the value at \( t = 2 \) is not included in this segment.
  
- **Segment 2 \( (2 \leq t < 5): \)** In this interval, \( f(t) = 2 \), which is represented as a horizontal line from (2, 2) to (5, 2). This line includes the point at \( t = 2 \) and excludes the point at \( t = 5 \), indicated by an open circle at (5, 2).

- **Segment 3 \( (5 \leq t < 7): \)** Here, \( f(t) = -t + 7 \), a decreasing linear function that starts from (5, 2) to (7, 0). The point (7, 0) has an open circle, showing that this endpoint is not included.

- **Segment 4 \( (t \geq 7): \)** The function becomes 0 and is represented as a horizontal line starting from \( t = 7 \) onward on the t-axis.

**(b) Express \( f(t) \) in Terms of the Unit Step Function \( u_c(t) \).**

\[ 
f(t) = 
\] 

The box below the problem is intended for expressing \( f(t) \) using the unit step function, \( u_c(t) \). This method allows for the combination of the piecewise function segments into a single expression using step functions that activate at specific points \( t = c \).
Transcribed Image Text:**(a) Sketch the Graph of the Given Function** The function \( f(t) \) is defined piecewise as follows: \[ f(t) = \begin{cases} t, & 0 \leq t < 2 \\ 2, & 2 \leq t < 5 \\ -t + 7, & 5 \leq t < 7 \\ 0, & t \geq 7 \end{cases} \] **Graph Explanation:** - **Segment 1 \( (0 \leq t < 2): \)** The function \( f(t) = t \) is a linear function, depicted as a straight line starting from the origin (0, 0) and ending at (2, 2). The point at (2, 2) is an open circle, indicating that the value at \( t = 2 \) is not included in this segment. - **Segment 2 \( (2 \leq t < 5): \)** In this interval, \( f(t) = 2 \), which is represented as a horizontal line from (2, 2) to (5, 2). This line includes the point at \( t = 2 \) and excludes the point at \( t = 5 \), indicated by an open circle at (5, 2). - **Segment 3 \( (5 \leq t < 7): \)** Here, \( f(t) = -t + 7 \), a decreasing linear function that starts from (5, 2) to (7, 0). The point (7, 0) has an open circle, showing that this endpoint is not included. - **Segment 4 \( (t \geq 7): \)** The function becomes 0 and is represented as a horizontal line starting from \( t = 7 \) onward on the t-axis. **(b) Express \( f(t) \) in Terms of the Unit Step Function \( u_c(t) \).** \[ f(t) = \] The box below the problem is intended for expressing \( f(t) \) using the unit step function, \( u_c(t) \). This method allows for the combination of the piecewise function segments into a single expression using step functions that activate at specific points \( t = c \).
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