8x + 12 Let f(x) : - 10x + 4 a. Determine the vertical intercept for f by evaluating f(0). f(0) Preview b. If the numerator of a ratio is 0 then the ratio has a value of 0 (such as , etc.). So horizontal 4' 12 intercepts (values of x that make f(x) = 0) occur whenever the function's numerator has a value of 0. Thus, horizontal intercept(s) for this function will occur when 8x + 12 = 0. What value(s) of x make this true? If there is more than one answer, enter values as a comma-separated list. Preview
8x + 12 Let f(x) : - 10x + 4 a. Determine the vertical intercept for f by evaluating f(0). f(0) Preview b. If the numerator of a ratio is 0 then the ratio has a value of 0 (such as , etc.). So horizontal 4' 12 intercepts (values of x that make f(x) = 0) occur whenever the function's numerator has a value of 0. Thus, horizontal intercept(s) for this function will occur when 8x + 12 = 0. What value(s) of x make this true? If there is more than one answer, enter values as a comma-separated list. Preview
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![Let \( f(x) = \frac{8x + 12}{x^2 - 10x + 4} \).
a. Determine the vertical intercept for \( f \) by evaluating \( f(0) \).
\[ f(0) = \] [Input Box] [Preview Button]
b. If the numerator of a ratio is 0, then the ratio has a value of 0 (such as \( \frac{0}{4}, \frac{0}{12}, \frac{0}{-3} \), etc.). So horizontal intercepts (values of \( x \) that make \( f(x) = 0 \)) occur whenever the function's numerator has a value of 0.
Thus, horizontal intercept(s) for this function will occur when \( 8x + 12 = 0 \). What value(s) of \( x \) make this true? *If there is more than one answer, enter values as a comma-separated list.*
\[ x = \] [Input Box] [Preview Button]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9bdd44c0-80af-4006-aeb1-064d54c4c394%2F01815f7f-bf84-45a3-b33a-17df8cb1511a%2F8a2241l_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Let \( f(x) = \frac{8x + 12}{x^2 - 10x + 4} \).
a. Determine the vertical intercept for \( f \) by evaluating \( f(0) \).
\[ f(0) = \] [Input Box] [Preview Button]
b. If the numerator of a ratio is 0, then the ratio has a value of 0 (such as \( \frac{0}{4}, \frac{0}{12}, \frac{0}{-3} \), etc.). So horizontal intercepts (values of \( x \) that make \( f(x) = 0 \)) occur whenever the function's numerator has a value of 0.
Thus, horizontal intercept(s) for this function will occur when \( 8x + 12 = 0 \). What value(s) of \( x \) make this true? *If there is more than one answer, enter values as a comma-separated list.*
\[ x = \] [Input Box] [Preview Button]
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