A skeletal structure for perchlorate (CIO) is shown below. Starting from this structure, complete the Lewis structure that follows the octet rule on all atoms. O I CI O Click to edit mecule O

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### Understanding Lewis Structures: Perchlorate Ion Example (ClO₄⁻)

**Question 3 of 14**

**Task:** A skeletal structure for perchlorate (ClO₄⁻) is shown below. Starting from this structure, complete the Lewis structure that follows the octet rule on all atoms.

![Perchlorate Ion Structure](Image_Link)

#### Description of Graph/Diagram:

In the diagram provided, which represents the skeletal structure of the perchlorate ion (ClO₄⁻), a central chlorine (Cl) atom is connected to four surrounding oxygen (O) atoms. Each connection is represented by a single line, which signifies a single bond between the chlorine atom and each oxygen atom.

- **Central Atom:** Chlorine (Cl)
- **Surrounding Atoms:** Four oxygen (O) atoms, each bonded to the central chlorine atom.

#### Steps to Complete the Lewis Structure:

1. **Count the Total Valence Electrons:**
   - Chlorine (Cl) has 7 valence electrons.
   - Each Oxygen (O) atom has 6 valence electrons, and with four O atoms, this totals 24 valence electrons.
   - The perchlorate ion carries a -1 charge, so add an additional electron.
   - Total valence electrons = 7 (from Cl) + 24 (from O atoms) + 1 (extra electron for the charge) = 32 valence electrons.

2. **Place Electrons Around Each Atom to Satisfy the Octet Rule:**
   - Start by placing a single bond (2 electrons) between Cl and each O atom, which uses up 8 electrons (4 bonds x 2 electrons per bond).
   - Distribute the remaining 24 electrons around each O atom to complete their octets.
   - Each O atom requires 6 more electrons to complete its octet, resulting in 24 electrons (4 O atoms x 6 electrons per O atom).

3. **Check the Chlorine Atom:**
   - The chlorine atom should be checked to ensure it follows the octet rule. Chlorine in this structure may need to share its electrons by forming double bonds with one or more oxygens to fulfill the octet requirement.

This exercise illustrates the importance of understanding the electron configuration around each atom to adhere to the octet rule while also considering the overall charge on the ion.
Transcribed Image Text:### Understanding Lewis Structures: Perchlorate Ion Example (ClO₄⁻) **Question 3 of 14** **Task:** A skeletal structure for perchlorate (ClO₄⁻) is shown below. Starting from this structure, complete the Lewis structure that follows the octet rule on all atoms. ![Perchlorate Ion Structure](Image_Link) #### Description of Graph/Diagram: In the diagram provided, which represents the skeletal structure of the perchlorate ion (ClO₄⁻), a central chlorine (Cl) atom is connected to four surrounding oxygen (O) atoms. Each connection is represented by a single line, which signifies a single bond between the chlorine atom and each oxygen atom. - **Central Atom:** Chlorine (Cl) - **Surrounding Atoms:** Four oxygen (O) atoms, each bonded to the central chlorine atom. #### Steps to Complete the Lewis Structure: 1. **Count the Total Valence Electrons:** - Chlorine (Cl) has 7 valence electrons. - Each Oxygen (O) atom has 6 valence electrons, and with four O atoms, this totals 24 valence electrons. - The perchlorate ion carries a -1 charge, so add an additional electron. - Total valence electrons = 7 (from Cl) + 24 (from O atoms) + 1 (extra electron for the charge) = 32 valence electrons. 2. **Place Electrons Around Each Atom to Satisfy the Octet Rule:** - Start by placing a single bond (2 electrons) between Cl and each O atom, which uses up 8 electrons (4 bonds x 2 electrons per bond). - Distribute the remaining 24 electrons around each O atom to complete their octets. - Each O atom requires 6 more electrons to complete its octet, resulting in 24 electrons (4 O atoms x 6 electrons per O atom). 3. **Check the Chlorine Atom:** - The chlorine atom should be checked to ensure it follows the octet rule. Chlorine in this structure may need to share its electrons by forming double bonds with one or more oxygens to fulfill the octet requirement. This exercise illustrates the importance of understanding the electron configuration around each atom to adhere to the octet rule while also considering the overall charge on the ion.
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