A simply supported beam is subjected to a uniform service dead load of 1.0 kips/ft (including the weight of the beam) and uniform service live load of 2.5 kips/ft. The beam is 40 feet long, The beam has continuous lateral support, and A572 Grade 50 steel is used. A572 Grade 50 steel has Fy = 50 ksi and Fu = 65 ksi. Is a W30 × 116 adequate from flexure and shear? Check both LRFD and ASD. Is the beam adequate from deflectio
A simply supported beam is subjected to a uniform service dead load of 1.0 kips/ft (including the weight of the beam) and uniform service live load of 2.5 kips/ft. The beam is 40 feet long, The beam has continuous lateral support, and A572 Grade 50 steel is used. A572 Grade 50 steel has Fy = 50 ksi and Fu = 65 ksi. Is a W30 × 116 adequate from flexure and shear? Check both LRFD and ASD. Is the beam adequate from deflectio
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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A simply supported beam is subjected to a uniform service dead load of 1.0 kips/ft (including the weight of the beam) and uniform service live load of 2.5 kips/ft. The beam is 40 feet long, The beam has continuous lateral support, and A572 Grade 50 steel is used. A572 Grade 50 steel has Fy = 50 ksi and Fu = 65 ksi.
- Is a W30 × 116 adequate from flexure and shear?
Check both LRFD and ASD. - Is the beam adequate from deflection if it allows
maximum deflection of L/360 (dead load + live
load)?

Transcribed Image Text:Wp= 1.0kA
Wz = 2.5k'A
W30 x 116
40'-
WųL
(LRFD)
2
Max shear load
WaL
(ASD)
Max shear load

Transcribed Image Text:W30x116
A =
34.20
in.^2
d =
30.000
in.
tw =
0.565
in.
bf =
10.500
in.
tf =
0.850
in.
T=
26-1/2
in.
k =
1.5000
in.
k1 =
1.1250
in.
5-1/2
in.
gage =
rt =
%3D
2.640
in.
d/Af =
3.36
Ix =
4930.00
in. ^4
Sx =
329.00
in.^3
rx =
12.000
in.
ly =
164.00
in.^4
Sy =
31.30
in.^3
ry =
2.190
in.
Zx =
378.00
in.^3
Zy =
J =
49.20
in.^3
6.43
in.^4
Cw =
34900
in. ^6
a =
118.55
in.
Wno =
76.50
in. ^2
Św =
171.00
in.^4
%3D
Qf =
61.50
in.^3
Qw =
187.00
in.^3
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