A simply supported beam hinged at A and supported at C, is carrying a distributed load and a point load (see Fig. 1). The beam has a Young Modulus E = 80 GPa and a constant depth of 400 mm. The moment of inertia of the beam is limited to be I = 255 x 10-4 m*. P- 120 KN 9. 15 KN/m 4 On Figure 1 (a) (0 Write the bending moment expression using Macauley's method. (ii) Determine the bending moment at A. (ii) Determine the bending moment at B. (iv) Determine the bending moment at C.

A simply supported beam hinged at A and supported at C, is carrying a distributed load and a point load (see Fig. 1). The beam has a Young Modulus E = 80 GPa and a constant depth of 400 mm. The moment of inertia of the beam is limited to be I = 255 x 10-4 m*. P- 120 KN 9. 15 KN/m 4 On Figure 1 (a) (0 Write the bending moment expression using Macauley's method. (ii) Determine the bending moment at A. (ii) Determine the bending moment at B. (iv) Determine the bending moment at C.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

A simply supported beam hinged at A and supported at C, is carrying a
distributed load and a point load (see Fig. 1). The beam has a Young
Modulus E = 80 GPa and a constant depth of 400 mm. The moment of
inertia of the beam is limited to be I = 255 x 10-4 m*.
1.
P- 120 KN
9 15 KN/m
4 (m)
2 (m)
Figure 1
(a) (i) Write the bending moment expression using Macauley's
method.
(ii) Determine the bending moment at A.
(ii) Determine the bending moment at B.
(iv) Determine the bending moment at C.
(v) Derive the deflection equation and find the value of the
integration constants.
(vi) Find the deflection at

b)
Fig. 2 shows the shear force (KN) and bending moment (KNm)
diagrams for the beam in Fig. 1.
P- 120
9- 15
4 (m
2 (m)
3 sec. 3)
56.25
30
63.75
225
Mx)
Figure 2 Shear force and bending moment diagram
(i) Find the maximum shear stress at point A.

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